120 CHAPTER 6. CONTINUOUS FUNCTIONS

Theorem 6.10.3 Suppose f is a continuous function defined on [a,b]. Then thereexists a sequence of polynomials, {pn} which converges uniformly to f on [a,b].

Proof: For t ∈ [0,1] , let h(t) = a+(b−a) t. Thus h maps [0,1] one to one and onto[a,b] . Thus f ◦h is a continuous function defined on [0,1] . It follows there exists a sequenceof polynomials {pn} defined on [0,1] which converges uniformly to f ◦h on [0,1]. Thus forevery ε > 0 there exists Nε such that if n≥ Nε , then for all t ∈ [0,1] , | f ◦h(t)− pn (t)|< ε.However, h is onto and one to one and so for all x ∈ [a,b],

∣∣ f (x)− pn(h−1 (x)

)∣∣ < ε.

Now note that the function x→ pn(h−1 (x)

)is a polynomial because h−1 (x) = x−a

b−a . Morespecifically, if pn (t) = ∑

mk=0 aktk it follows

pn(h−1 (x)

)=

m

∑k=0

ak

(x−ab−a

)k

which is clearly another polynomial.

6.11 Ascoli Arzela TheoremThis is a major result which plays the role of the Heine Borel theorem for the set of con-tinuous functions. I will give the version which holds on an interval, although this theoremholds in much more general settings. First is a definition of what it means for a collec-tion of functions to be equicontinuous. In words, this happens when they are all uniformlycontinuous simultaneously.

Definition 6.11.1 Let S ⊆ C ([0,T ]) where C ([0,T ]) denotes the set of functionswhich are continuous on the interval [0,T ] . Thus S is a set of functions. Then S is said tobe equicontinuous if whenever ε > 0 there exists a δ > 0 such that whenever f ∈ S and|x− y|< δ , it follows

| f (x)− f (y)|< ε

The set of functions is said to be uniformly bounded if there is a positive number M suchthat for all f ∈ S,

sup{| f (x)| : x ∈ [0,T ]} ≤M

Then the Ascoli Arzela theorem says the following in which it is assumed the functionshave values in F although this could be generalized.

Theorem 6.11.2 Let { fn}∞

n=1 ⊆ C ([0,T ]) be uniformly bounded and equicontinu-ous. Then there exists a uniformly Cauchy subsequence.

Proof: Let ε > 0 be given and let δ correspond to ε/4 in the definition of equicontinu-ity. Let 0= x0 < x1 < · · ·< xn = T where these points are uniformly spaced and the distancebetween successive points is T/n < δ . Then the points { fn (x0)}∞

n=1 is a bounded set in F.By the Heine Borel theorem, there is a convergent subsequence

{fk(0) (x0)

}∞

k(0)=1. Thus{k (0)} denotes a strictly increasing sequence of integers. Then the same theorem impliesthere is a convergent subsequence of this one, denoted as k (1) such that limk(1)→∞ fk(1) (x0)

and limk(1)→∞ fk(1) (x1) both exist. Then take a subsequence of{

fk(1)}

called k (2) suchthat for xi = x0,x1,x2, limk(2)→∞ fk(2) (xi) exists. This can be done because if a sequenceconverges then every subsequence converges also. Continue this way. Denote by {k} the

120 CHAPTER 6. CONTINUOUS FUNCTIONSTheorem 6.10.3 Suppose f is a continuous function defined on |a,b|. Then thereexists a sequence of polynomials, { p,} which converges uniformly to f on {a,b}.Proof: For t¢ € [0,1], let h(t) =a+(b—a)t. Thus h maps [0,1] one to one and onto[a,b]. Thus f oh is a continuous function defined on [0, 1] . It follows there exists a sequenceof polynomials {p,} defined on [0, 1] which converges uniformly to f oh on [0, 1]. Thus forevery € > 0 there exists Ne such that if n > Ne, then for all t € [0,1] ,|foh(t) — pa (d)| <e.However, h is onto and one to one and so for all x € [a,b], |f (x) — pn (A! (x))| < €.Now note that the function x + p, (A! (x)) is a polynomial because h7! (x) = #=*. Morespecifically, if py (t) = Li" 9 axt* it followspoll) = Sa (22)k=0which is clearly another polynomial. §§6.11 Ascoli Arzela TheoremThis is a major result which plays the role of the Heine Borel theorem for the set of con-tinuous functions. I will give the version which holds on an interval, although this theoremholds in much more general settings. First is a definition of what it means for a collec-tion of functions to be equicontinuous. In words, this happens when they are all uniformlycontinuous simultaneously.Definition 6.11.1 Ler sc C([0,T]) where C([0,T]) denotes the set of functionswhich are continuous on the interval [0,T]. Thus S is a set of functions. Then S is said tobe equicontinuous if whenever € > 0 there exists a 6 > 0 such that whenever f € S and|x —y| < 6, it followsIf (x) -—fO) <€The set of functions is said to be uniformly bounded if there is a positive number M suchthat for all f €S,sup {|f (x)| :x € [0,7]} <MThen the Ascoli Arzela theorem says the following in which it is assumed the functionshave values in F although this could be generalized.Theorem 6.11.2 Lez {f, nat © C([0,T]) be uniformly bounded and equicontinu-ous. Then there exists a uniformly Cauchy subsequence.Proof: Let € > 0 be given and let 6 correspond to €/4 in the definition of equicontinu-ity. LetO =x <x, <-+- <x, =T where these points are uniformly spaced and the distancebetween successive points is T/n < 6. Then the points {f;, (xo) };_, is a bounded set in F.By the Heine Borel theorem, there is a convergent subsequence { Sk(0) (%0) broyar Thus{k(0)} denotes a strictly increasing sequence of integers. Then the same theorem impliesthere is a convergent subsequence of this one, denoted as k (1) such that lim(1).. fx(1) (xo)and limy,)-400 f¢(1) (1) both exist. Then take a subsequence of { Fit) } called k(2) suchthat for x; = x0,x1,%2, limg(2) +00 Sk(2) (x;) exists. This can be done because if a sequenceconverges then every subsequence converges also. Continue this way. Denote by {k} the