376 CHAPTER 13. FOURIER TRANSFORMS

These functions are clearly quite specialized. Therefore, the following theorem is some-what surprising.

Theorem 13.1.4 For each p ≥ 1, p < ∞,G is dense in Lp (Rn). Since G is count-able, this shows that Lp (Rn) is separable.

Proof: Let f ∈ Lp (Rn) . Then there exists g ∈Cc (Rn) such that ∥ f −g∥p < ε . Now letb > 0 be large enough that ∫

Rn

(e−b|x|2

)pdx < ε

p.

Then x→ g(x)eb|x|2 is in Cc (Rn)⊆C0 (Rn) . Therefore, from Lemma 13.1.3 there existsψ ∈ G such that ∥∥∥geb|·|2 −ψ

∥∥∥∞

< 1

Therefore, letting φ (x)≡ e−b|x|2ψ (x) it follows that φ ∈ G and for all x ∈ Rn,

|g(x)−φ (x)|< e−b|x|2

Therefore, (∫Rn |g(x)−φ (x)|p dx)1/p ≤

(∫Rn

(e−b|x|2

)pdx)1/p

< ε . It follows

∥ f −φ∥p ≤ ∥ f −g∥p +∥g−φ∥p < 2ε.■

From now on, we can drop the restriction that the coefficients of the polynomials in Gare rational. We also drop the restriction that a is rational. Thus G will be finite sums offunctions which are of the form p(x)e−a|x|2 where the coefficients of p are complex anda > 0.

The following lemma is also interesting even if it is obvious.

Lemma 13.1.5 For ψ ∈ G , p a polynomial, and α,β multi-indices, Dα ψ ∈ G andpψ ∈ G . Also

sup{|xβ Dαψ(x)| : x ∈ Rn}< ∞

Thus these special functions are infinitely differentiable (smooth). They also have theproperty that they and all their partial derivatives vanish as |x| → ∞.

Let G be the functions of Definition 13.1.2 except, for the sake of convenience, removeall references to rational numbers. Thus G consists of finite sums of polynomials havingcoefficients in C times e−a|x|2 for some a > 0. The idea is to first understand the Fouriertransform on these very specialized functions.

Definition 13.1.6 For ψ ∈ G Define the Fourier transform F and the inverse Four-ier transform, F−1 by

Fψ(t)≡ (2π)−n/2∫Rn

e−it·xψ(x)dx, F−1

ψ(t)≡ (2π)−n/2∫Rn

eit·xψ(x)dx.

where t ·x≡∑ni=1 tixi. Note there is no problem with this definition because ψ is in L1 (Rn)

and therefore,∣∣eit·xψ(x)

∣∣≤ |ψ(x)| , an integrable function.

376 CHAPTER 13. FOURIER TRANSFORMSThese functions are clearly quite specialized. Therefore, the following theorem is some-what surprising.Theorem 13.1.4 For each p>1,p<~,@ is dense in L? (R"). Since Y is count-able, this shows that L? (R") is separable.Proof: Let f € L? (R"). Then there exists g € C; (IR") such that || f — g||,, < €. Now letb > 0 be large enough that| (ete) ax <e?.Then x > g(x) eblel’ is in C, (R") C Co (R"). Therefore, from Lemma 13.1.3 there existsw € & such thatTherefore, letting ¢ (a) = e ble! y (x) it follows that @ € Y and for all x € R",2ro yflg (@) — 6 (a)|<e Pr1/Therefore, (Jin |g (#) — (a) |? dx)!” < (Jie (eH) "ax) ” < e. It followsIf-9ll, <llf-sllp+lla—¢ll, < 2€.mFrom now on, we can drop the restriction that the coefficients of the polynomials in ¥are rational. We also drop the restriction that a is rational. Thus ¥ will be finite sums offunctions which are of the form p (a) ell” where the coefficients of p are complex anda>0.The following lemma is also interesting even if it is obvious.Lemma 13.1.5 For yw €¥ , p a polynomial, and a,B multi-indices, D’w € Y andpwe@. Alsosup{|a’D* w(a)|: 2 €R"} <Thus these special functions are infinitely differentiable (smooth). They also have theproperty that they and all their partial derivatives vanish as |a| — 9.Let Y be the functions of Definition 13.1.2 except, for the sake of convenience, removeall references to rational numbers. Thus ¥ consists of finite sums of polynomials having. . . 2 . . .coefficients in C times e~“!”! for some a > 0. The idea is to first understand the Fouriertransform on these very specialized functions.Definition 13.1.6 For y € G Define the Fourier transform F and the inverse Four-ier transform, F~! byFy(t) = (2m)-"? I ety (a)dx, Fly(t) = 2m)" I et y(a)de.where t- x = Yi_, tix;. Note there is no problem with this definition because y is in L' (R")and therefore, |e** y(a)| < |w(a)|, an integrable function.