642 CHAPTER 23. REPRESENTATION THEOREMS

Proof: There is only one possible way to extend this functional to obtain a linear func-tional and the arguments are identical with those of Theorem 10.7.8 so I will refer to thisearlier theorem for these arguments. In particular, you must have

Λ( f ) = Λ(Re f )+ iΛ(Im f ) = Λ(Re f )+−Λ(Re f )−

+i(Λ(Im f )+−Λ(Im f )−

)= λ (Re f )+−λ (Re f )−+ i

(λ (Im f )+−λ (Im f )−

)Since the nature of the functions is different, being continuous here rather than only mea-surable, the only thing left is to show the claim about continuity of Λ in case of 23.14.

What of the last claim that |Λ f | ≤ λ (| f |)? Let ω have |ω| = 1 and |Λ f | = ωΛ( f ) .Since Λ is linear,

|Λ f |= ωΛ( f ) = Λ(ω f ) = Λ(Reω f )≤ Λ(Re(ω f )+

)= λ

(Re(ω f )+

)≤ λ (| f |)≤C∥ f∥

∞■

Corollary 23.7.5 Let L ∈L (C0 (X) ,C) . Then there exists Λ ∈L (C0 (X) ,C) whichsatisfies ∥Λ∥= ∥L∥ but also Λ is a positive linear functional meaning it f ≥ 0, then Λ( f )≥0.

Proof: Let λ be the righteous functional defined in Lemma 23.7.3 which satisfies|λ ( f )| ≤ ∥L∥∥ f∥

∞. Then let Λ be its extension defined in Lemma 23.7.4 which also satis-

fies |Λ( f )| ≤ ∥L∥∥ f∥∞. Then this is a positive linear functional and ∥Λ∥ ≤ ∥L∥. However,

from the definition of λ ,

|Lg| ≤ λ (|g|) = Λ(|g|)≤ ∥Λ∥∥g∥∞

and so also ∥L∥ ≤ ∥Λ∥. ■

23.7.2 The Riesz Representation TheoremWhat follows is the Riesz representation theorem for C0(X)′.

Theorem 23.7.6 Let L ∈ (C0(X))′ for X a locally compact Hausdorf space. Thenthere exists a σ algebra F and a finite Radon measure µ and a function σ ∈ L∞(X ,µ)such that for all f ∈C0 (X) ,

L( f ) =∫

Xf σdµ.

Furthermore, µ (X) = ∥L∥ , |σ |= 1 a.e. and if ν (E)≡∫

E σdµ then µ = |ν | .

Proof: From Corollary 23.7.5, there exists a positive linear functional Λ defined onC0 (X) with ∥Λ∥ = ∥L∥ . Then let µ be the Radon measure representing Λ for which, byLemma 23.7.2, µ (X) = ∥Λ∥= ∥L∥.

For f ∈ Cc (X) , |L f | ≤ λ (| f |) = Λ(| f |) =∫

X | f |dµ = ∥ f∥L1(µ).Since µ is both innerand outer regular thanks to it being finite, Cc(X) is dense in L1(X ,µ). (See Theorem 12.2.4for more than is needed.) Thus there is a unique extension of L to L̃ ∈

(L1(X ,µ)

)′ and

642 CHAPTER 23. REPRESENTATION THEOREMSProof: There is only one possible way to extend this functional to obtain a linear func-tional and the arguments are identical with those of Theorem 10.7.8 so I will refer to thisearlier theorem for these arguments. In particular, you must haveA(f) = A(Ref)+iA(Imf) = A(Ref)* —A(Ref)~+i(A(Imf)* —A(Imf))A(Ref)* —A (Ref) +i(A (Im f)* —A (Im f) )Since the nature of the functions is different, being continuous here rather than only mea-surable, the only thing left is to show the claim about continuity of A in case of 23.14.What of the last claim that |Af| < A (|f|)? Let @ have |@| = 1 and |Af| = @A(f).Since A is linear,|Af| = @A(f) = A(@f) = A(Re@f) < A(Re(@f)”)=A (Re(@f)") <A(IF\) SCllfll..Corollary 23.7.5 Let L € Y (Co(X),C). Then there exists A € Y (Co(X),C) whichsatisfies ||A|| = ||L|| but also A is a positive linear functional meaning it f > 0, then A(f) >0.Proof: Let A be the righteous functional defined in Lemma 23.7.3 which satisfies|A (f)| < |IEZII || f|..- Then let A be its extension defined in Lemma 23.7.4 which also satis-fies |A(f)| < ||Z|| || f ||... Then this is a positive linear functional and ||A|| < ||L||. However,from the definition of /,[Lg] <A (|s|) =A(Igl) < HAM lgll..and so also ||Z|| < ||A||. i23.7.2 The Riesz Representation TheoremWhat follows is the Riesz representation theorem for Co(X)’.Theorem 23.7.6 Let L € (Co(X))! for X a locally compact Hausdorf space. Thenthere exists a o algebra F and a finite Radon measure wt and a function o € L”(X,U)such that for all f € Co(X),Lif) = | fod.Furthermore, [1 (X) = ||L||, |o| = 1 ae. and if v(E) = Jy od then u = |v|.Proof: From Corollary 23.7.5, there exists a positive linear functional A defined onCo (X) with ||A]| = ||Z||. Then let be the Radon measure representing A for which, byLemma 23.7.2, u(X) = ||Al| = ||ZI|.For f € C.(X),|Lf| <A (II) = ACAD = Sx |AldH = Ilfllc1quy-Since # is both innerand outer regular thanks to it being finite, C.(X) is dense in L'(X,). (See Theorem 12.2.4for more than is needed.) Thus there is a unique extension of L to L € (LI(X ; u))' and