31.3. DOOB OPTIONAL SAMPLING CONTINUOUS CASE 839

To show this, first note that ω ∈ [τ ≤ a] if and only if there exists t ≤ a such that X (t)(ω)∈H. This follows from continuity and the fact that H is closed. Thus τn ≤ a for all nbecause for some t ≤ a, X (t) ∈ H ⊆ Bn for all n. Next suppose ω ∈ [τn ≤ a] for all n.Then for δ n ↓ 0, there exists tn ∈ [0,a+δ n] such that X (tn)(ω) ∈ Bn. It follows there is asubsequence, still denoted by tn such that tn → t ∈ [0,a]. By continuity of X , it must bethe case that X (t)(ω) ∈H and so ω ∈ [τ ≤ a] . This shows the above formula. Now by thefirst part, each [τn ≤ a] ∈Fa and so [τ ≤ a] ∈Fa also. ■

Another useful result for real valued stochastic process is the following in which conti-nuity is generalized to lower semicontinuity.

Proposition 31.3.10 Let X (t) be a real valued stochastic process which is Ft adaptedfor a normal filtration Ft , with the property that t→ X (t) is lower semicontinuous. Then

τ ≡ inf{t : X (t)> α}

is a stopping time.

Proof: As above, for each m > 0,

[τ = a] =(∩∞

n=m∪t∈[a,a+ 1n ][X (t)> α]

)∩(∩t∈[0,a) [X (t)≤ α]

)Now

∩t∈[0,a) [X (t)≤ α]⊆ ∩t∈[0,a),t∈Q [X (t)≤ α]

If ω is in the right side, then for arbitrary t < a, let tn ↓ t where tn ∈ Q and t < a. ThenX (t)≤ liminfn→∞ X (tn)≤ α and so ω is in the left side also. Thus

∩t∈[0,a) [X (t)≤ α] = ∩t∈[0,a),t∈Q [X (t)≤ α]

∪t∈[a,a+ 1n ][X (t)> α]⊇ ∪t∈[a,a+ 1

n ],t∈Q[X (t)> α]

If ω is in the left side, then for some t in the given interval, X (t) > α. If for all s ∈[a,a+ 1

n

]∩Q you have X (s)≤ α, then you could take sn→ t where X (sn)≤ α and con-

clude from lower semicontinuity that X (t) ≤ α also. Thus there is some rational s whereX (s)> α and so the two sides are equal. Hence,

[τ = a] =(∩∞

n=m∪t∈[a,a+ 1n ],t∈Q

[X (t)> α])∩(∩t∈[0,a),t∈Q [X (t)≤ α]

)The first set on the right is in Fa+(1/m) and so is the next set on the right. Hence [τ = a] ∈∩mFa+(1/m) = Fa. To be a stopping time, one needs [τ ≤ a] ∈Fa. What of [τ < a]? Thisequals ∪t∈[0,a) [X (t)> α] = ∪t∈[0,a)∩Q [X (t)> α] ∈Fa, the equality following from lowersemi-continuity. Thus [τ ≤ a] = [τ = a]∪ [τ < a] ∈Fa. ■

31.3.2 The Optional Sampling Theorem Continuous Case

Proposition 31.3.11 Let M (t) , t ≥ 0 be a martingale with values in E a separableBanach space and let τ be a bounded stopping time whose maximum is T . Then M (τ) isFτ measurable and in fact,

∫Ω∥M (τ)∥dP < ∞. Letting

τk (ω)≡∞

∑n=0

Xτ−1((n2−k,(n+1)2−k]) (ω)(n+1)2−k

be the discrete stopping times. {M (τk)} are uniformly integrable on FT .

31.3. DOOB OPTIONAL SAMPLING CONTINUOUS CASE 839To show this, first note that @ € [Tt < a] if and only if there exists t < a such that X (t) (@) €H. This follows from continuity and the fact that H is closed. Thus 7, < a for all nbecause for some t < a, X(t) © H C B, for all n. Next suppose @ € [t, <a] for all n.Then for 6, | 0, there exists t, € [0,a+6,] such that X (t,) (@) € By. It follows there is asubsequence, still denoted by f, such that t, >t € [0,a]. By continuity of X, it must bethe case that X (t) (@) € H and so @ € [t < a]. This shows the above formula. Now by thefirst part, each [t, < a] € Fq and so [t < a] € F, also. HHAnother useful result for real valued stochastic process is the following in which conti-nuity is generalized to lower semicontinuity.Proposition 31.3.10 Let X (t) be a real valued stochastic process which is F, adaptedfor anormal filtration F,, with the property that t — X (t) is lower semicontinuous. ThenT=inf{t: X(t) >a}is a stopping time.Proof: As above, for each m > 0,[=a] = (mn Upefa ast] EX () > A) 9 (Meow X ) < al)NowMe[0,a) LX (t) < @] C Mefo,a) req [IX (4) < @]If @ is in the right side, then for arbitrary t < a, let t, | t where t, € Q and t < a. ThenX (t) < liminf,,..X (t,) < a and so @ is in the left side also. ThusMe[0,a) IX (4) < @] = Mefo.a) req [IX (4) < @]Vre[aa+2] [X (t) > a@] 2 rel, [X (t) > a]aa++]t€QIf @ is in the left side, then for some f in the given interval, X (t) > a. If for all s €[a,a+ +] MQ you have X (s) < a, then you could take s, — ¢ where X (sy) < @ and con-clude from lower semicontinuity that X (t) < @ also. Thus there is some rational s whereX (s) > a and so the two sides are equal. Hence,[=a] = (Man Urefaart nea X () > 2) 9 (Mrcioazeo IX (1) < al)The first set on the right is in 7,4 (1 /m) and so is the next set on the right. Hence [t = a] €mF a+(1/m) = Fa. To be a stopping time, one needs [t < a] € F,. What of [t < a]? Thisequals U;<(0,a) [X (t) > &] = Usefoayna IX (4) > @] € Fa, the equality following from lowersemi-continuity. Thus [t < a] = [tT=a]U[t <a] € Fy.31.3.2 The Optional Sampling Theorem Continuous CaseProposition 31.3.11 Let M(t) ,t > 0 be a martingale with values in E a separableBanach space and let t be a bounded stopping time whose maximum is T. Then M(t) isF, measurable and in fact, {9 ||M (t)||dP < ©. LettingTh (@) = Le ((n2-*,(n41)2-4)) (@) (n + 1) Q-*be the discrete stopping times. {M (t,)} are uniformly integrable on Fr.