844 CHAPTER 31. OPTIONAL SAMPLING THEOREMS

=mn

∑k=0

Xτ−1((tn

k ,tnk+1])

E(

X (T ) |Ftnk+1

)≥

mn

∑k=0

Xτ−1((tn

k ,tnk+1])

X(tnk+1)= X (τn)

Thus this is indeed a sub-martingale. The same argument holds in case X is a martingale.One simply replaces the inequalities with equal signs.

Having shown that X (0) ,X (τn) ,X (T ) is a sub-martingale,∫[X(τn)≥λ ]

X (τn)dP ≤∫[X(τn)≥λ ]

E (X (T ) |Fτn)dP

=∫

E(X[X(τn)≥λ ]X (T ) |Fτn

)dP

=∫[X(τn)≥λ ]

X (T )dP

If the interest were in a martingale where X (t) is in a Banach space, you would simply doall the remaining analysis for the sub-martingale ∥X (t)∥. Thus, from now on, I will mainlyconsider a real sub-martingale. From maximal estimates, for example Theorem 29.3.14,

P([X (τn)≥ λ ])≤ 1λ

∫Ω

X (T )+ dP =1λ

∫Ω

X (T )dP

and now it follows from the above that the random variables X (τn) are equiintegrable.Recall this means that

limλ→∞

supn

∫[X(τn)≥λ ]

X (τn)dP = 0

Hence they are uniformly integrable and bounded in L1.To verify again that |X (τ)| is integrable, note that by right continuity, X (τn)→ X (τ)

pointwise. Apply the Vitali convergence theorem to obtain∫Ω

|X (τ)|dP = limn→∞

∫Ω

|X (τn)|dP≤∫

X (T )dP < ∞. ■

Theorem 31.3.16 Let M (t) be a right continuous martingale with values in aseparable Banach space adapted to a normal filtration. Let σ ,τ be two stopping timessuch that τ is bounded. Then M (σ ∧ τ) = E (M (τ) |Fσ ) . If X is a real sub-martingale,X (σ ∧ τ)≤ E (X (τ) |Fσ ) .

Proof: Letting M (t) , t ≥ 0 be a martingale with values in a separable Banach spaceadapted to a filtration Ft . Let τk and σ k be the discreet stopping times such that τk is atleast as big as τ but within 2−k of τ discussed earlier. Therefore, from the optional samplingtheorem for discreet martingales in Theorem 31.2.1,

M (σn∧ τn) = E (M (τn) |Fσn)

Now let A ∈Fσ . Using Proposition 31.3.8 as needed, Fσ ⊆Fσn and∫A

M (σn∧ τn)dP =∫

AE (M (τn) |Fσn)dP

Fσ⊆Fσn=∫

AM (τn)dP

844 CHAPTER 31. OPTIONAL SAMPLING THEOREMSpe (pat, 1) (x (T) Fi.)2 de (tstal)* (1) =X (tn)Thus this is indeed a sub-martingale. The same argument holds in case X is a martingale.One simply replaces the inequalities with equal signs.Having shown that X (0) ,X (T,) ,X (T) is a sub-martingale,/ X (T,) dP[X(Tn) >A]IAE (X (T) |.¥Fz,,) dPFe coyon = Fe)= Le (2ix(e,)>ajX (1) | Fr,) dP= | X(T) dPX(t) 2A)If the interest were in a martingale where X (t) is in a Banach space, you would simply doall the remaining analysis for the sub-martingale ||X (+) ||. Thus, from now on, I will mainlyconsider a real sub-martingale. From maximal estimates, for example Theorem 29.3.14,P([X(t») > Al) < x | xrytar= x [x (ryarand now it follows from the above that the random variables X (t,,) are equiintegrable.Recall this means thatlim sup [ X (T,)dP =0J[X(T)>A]Ano nHence they are uniformly integrable and bounded in L!.To verify again that |X (T)| is integrable, note that by right continuity, X (t,) + X (tT)pointwise. Apply the Vitali convergence theorem to obtain[x @lar= tim [x ear < [x(r)aP <o.Theorem 31.3.16 ze: u (t) be a right continuous martingale with values in aseparable Banach space adapted to a normal filtration. Let o,t be two stopping timessuch that t is bounded. Then M(o At) = E(M(t)|-¥%o). If X is a real sub-martingale,X (OAT) <E(X (Tt) | Fo).Proof: Letting M(t) ,t > 0 be a martingale with values in a separable Banach spaceadapted to a filtration .Y,. Let t, and oO, be the discreet stopping times such that tT, is atleast as big as T but within 2~* of t discussed earlier. Therefore, from the optional samplingtheorem for discreet martingales in Theorem 31.2.1,M (0nA Tn) = E (M (Tn) |-Fo,)Now let A € ¥,. Using Proposition 31.3.8 as needed, Fo C Fo, andFoCPo[ Mountn)aP =f E(M (t)|Fo,)4P = * | w(z,)aPA A A