3.11. CONNECTED SETS 89

open set, U containing f (z) such that U∩A= /0. But then, the continuity of f and Theorem3.6.2 implies that f−1 (U) is an open set containing z such that f−1 (U)∩f−1 (A) = /0.Therefore, f−1 (B) contains no limit points of f−1 (A) . Similar reasoning implies f−1 (A)contains no limit points of f−1 (B). It follows that X is separated by f−1 (A) and f−1 (B) ,contradicting the assumption that X was connected. ■

An arbitrary set can be written as a union of maximal connected sets called connectedcomponents. This is the concept of the next definition.

Definition 3.11.4 Let S be a set and let p ∈ S. Denote by Cp the union of all con-nected subsets of S which contain p. This is called the connected component determined byp.

Theorem 3.11.5 Let Cp be a connected component of a set S in a metric space.Then Cp is a connected set and if Cp∩Cq ̸= /0, then Cp =Cq.

Proof: Let C denote the connected subsets of S which contain p. By Theorem 3.11.2,∪C = Cp is connected. If x ∈Cp ∩Cq, then from Theorem 3.11.2, Cp ⊇Cp ∪Cq and soCp ⊇Cq . The inclusion goes the other way by the same reason. ■

This shows the connected components of a set are equivalence classes and partition theset.

A set, I is an interval in R if and only if whenever x,y ∈ I then [x,y]⊆ I. The followingtheorem is about the connected sets in R.

Theorem 3.11.6 A set C in R is connected if and only if C is an interval.

Proof: Let C be connected. If C consists of a single point, p, there is nothing to prove.The interval is just [p, p] . Suppose p < q and p,q ∈C. You need to show (p,q)⊆C. If

x ∈ (p,q)\C

let C∩ (−∞,x) ≡ A, and C∩ (x,∞) ≡ B. Then C = A∪B and the sets A and B separate Ccontrary to the assumption that C is connected.

Conversely, let I be an interval. Suppose I is separated by A and B. Pick x ∈ A andy ∈ B. Suppose without loss of generality that x < y. Now define the set,

S≡ {t ∈ [x,y] : [x, t]⊆ A}

and let l be the least upper bound of S. Then l ∈ A so l /∈ B which implies l ∈ A. But ifl /∈ B, then for some δ > 0,

(l, l +δ )∩B = /0

contradicting the definition of l as an upper bound for S. Therefore, l ∈ B which impliesl /∈ A after all, a contradiction. It follows I must be connected. ■

This yields a generalization of the intermediate value theorem from one variable calcu-lus.

Corollary 3.11.7 Let E be a connected set in a metric space and suppose f : E → Rand that y ∈ ( f (e1) , f (e2)) where ei ∈ E. Then there exists e ∈ E such that f (e) = y.

Proof: From Theorem 3.11.3, f (E) is a connected subset of R. By Theorem 3.11.6f (E) must be an interval. In particular, it must contain y. This proves the corollary. ■

The following theorem is a very useful description of the open sets in R.