114 CHAPTER 5. LINE INTEGRALS AND CURVES

Note that from the above definition, it is obvious that the line integral is linear. Simplylet Pn refer to a uniform parition of [a,b] and let τn

j be the midpoint of[tn

j−1, tnj

]. Then for

a,b scalars and f,g vector valued functions which have integrals,

a∫

γ

f ·dγ +b∫

γ

g ·dγ

=

 limn→∞ a∑Pn f(

γ

(τn

j

))·(

γ

(tn

j

)− γ

(tn

j−1

))+ limn→∞ b∑Pn g

(τn

j

))·(

γ

(tn

j

)− γ

(tn

j−1

)) = lim

n→∞∑Pn

(af(γ(τ

nj))

+bg(γ(τ

nj)))·(γ(tn

j)− γ(tn

j−1))

≡∫

γ

(af+bg) ·dγ

Another issue is whether the integral depends on the parametrization associated with γ∗

or only on γ∗ and the direction of motion over γ∗. If φ : [c,d]→ [a,b] is a continuousnondecreasing function, then γ ◦φ : [c,d]→ Rp is also of bounded variation and yields thesame set of points in Rp with the same first and last points. The next theorem explains thatone can use either γ or γ ◦φ and get the same integral.

5.1.1 Change of Parameter

Theorem 5.1.3 Let φ be continuous and non-decreasing and γ is continuous andbounded variation. Then assuming that

∫γ

f ·dγ exists, so does∫

γ◦φ fd (γ ◦φ) and∫γ

f ·dγ =∫

γ◦φfd (γ ◦φ) . (5.1)

Proof: There exists δ > 0 such that if P is a partition of [a,b] such that ∥P∥ < δ ,

then∣∣∣∫γ

f ·dγ−S (P)∣∣∣ < ε. By Theorem 2.5.28, φ is uniformly continuous so there ex-

ists σ > 0 such that if Q is a partition of [c,d] with ∥Q∥ < σ ,Q = {s0, · · · ,sn} , then∣∣φ (s j)−φ(s j−1

)∣∣< δ . Thus letting P denote the points in [a,b] given by φ (s j) for s j ∈Q,it follows that ∥P∥< δ and so∣∣∣∣∣

∫γ

f ·dγ−n

∑j=1

f(γ (φ (τ j))) ·(γ (φ (s j))− γ

(φ(s j−1

)))∣∣∣∣∣< ε

where τ j ∈[s j−1,s j

]. Therefore, from the definition 5.1 holds and

∫γ◦φ f · d (γ ◦φ) exists

and equals∫

γf ·dγ . ■

This theorem shows that∫

γf ·dγ is independent of the particular parametrization γ used

in its computation in the sense that if φ is any nondecreasing continuous function fromanother interval, [c,d] , mapping onto [a,b] , then the same value is obtained by replacing γ

with γ ◦φ .

Lemma 5.1.4 Let φ : I → R be a function and I is an interval and suppose φ is 1−1 and continuous on I. Then φ is either strictly increasing or strictly decreasing on I.Furthermore, if φ is one to one and continuous on [a,b] then φ

−1 is continuous.

114 CHAPTER 5. LINE INTEGRALS AND CURVESNote that from the above definition, it is obvious that the line integral is linear. Simply|. Then forlet P, refer to a uniform parition of [a,b] and let tj, be the midpoint of |t EF fista,b scalars and f, g vector valued functions which have integrals,a[t-ay+b [g-dyY YZ limy 504 Lp, f ( (77 y(t" V(treac Gl) nD= Jim Cat (y (#5) + b8 (7 ¥(7}))) (1) —V(Ga))= | (at+oe) -dyYAnother issue is whether the integral depends on the parametrization associated with y*or only on ¥* and the direction of motion over y*. If @ : [c,d] — [a,b] is a continuousnondecreasing function, then yo @ : [c,d] — R? is also of bounded variation and yields thesame set of points in R? with the same first and last points. The next theorem explains thatone can use either y or yo @ and get the same integral.5.1.1 Change of ParameterTheorem 5.1.3 Ler @ be continuous and non-decreasing and ¥Y is continuous andbounded variation. Then assuming that J,f-dy exists, so does Jy.9 fd (yo@) and[are |) ta(re9). (5.1)Proof: There exists 5 > 0 such that if P is a partition of [a,b] such that ||P|| < 6,then | Jyf-dy—-S (P)| < €. By Theorem 2.5.28, @ is uniformly continuous so there ex-ists o > 0 such that if Q is a partition of [c,d] with ||Q|| < o,Q@ = {so,--- , sn}, then|@ (sj) —@ (s;-1)| < 6. Thus letting P denote the points in [a,b] given by @ (s;) for s; € Q,it follows that ||P|| < 6 and so[ ray Y 819 (2;)))-(r(0(s) -1(6(s;-1)))| <ewhere 7; € [sj-1,5;]. Therefore, from the definition 5.1 holds and J,,,f-d(yo@) existsand equals f,f-dy.This theorem shows that Jf -dy is independent of the particular parametrization y usedin its computation in the sense that if @ is any nondecreasing continuous function fromanother interval, [c,d], mapping onto [a,b] , then the same value is obtained by replacing ywith yo.Lemma 5.1.4 Let @ : 1 > R be a function and I is an interval and suppose @ is 1—1 and continuous on I. Then @ is either strictly increasing or strictly decreasing on I.Furthermore, if @ is one to one and continuous on |a,b] then @~! is continuous.