158 CHAPTER 6. MEASURES AND MEASURABLE FUNCTIONS

30. ↑Having defined the integral of nonnegative simple functions in the above problem,letting f be nonnegative and measurable. Define∫

f dµ ≡ sup{∫

sdµ : 0≤ s≤ f ,s simple}.

Show that if fn is nonnegative and measurable and n→ fn (ω) is increasing, showthat for f (ω) = limn→∞ fn (ω) , it follows that

∫f dµ = limn→∞

∫fndµ . Hint: Show∫

fndµ is increasing to something α ≤ ∞. Explain why∫

f dµ ≥ α. Now pick anonnegative simple function s ≤ f . For r ∈ (0,1) , [ fn > rs] ≡ En is increasing in nand ∪nEn = Ω. Tell why

∫fndµ ≥

∫XEn fndµ ≥ r

∫sdµ . Let n→ ∞ and show that

α ≥ r∫

sdµ . Now explain why α ≥ r∫

f dµ . Since r is arbitrary, α ≥∫

f dµ ≥ α .

31. ↑Show that if f ,g are nonnegative and measurable and a,b≥ 0, then∫(a f +bg)dµ = a

∫f dµ +b

∫gdµ

158 CHAPTER 6. MEASURES AND MEASURABLE FUNCTIONS30. Having defined the integral of nonnegative simple functions in the above problem,letting f be nonnegative and measurable. Define[ raw =sunf [sau :0<s < f.s-simpte}.Show that if f, is nonnegative and measurable and n > f,(@) is increasing, showthat for f (@) = limp... fn (@), it follows that f fdu = lim, +. f frdu. Hint: ShowJ frdw is increasing to something @ < co. Explain why f fdu > a. Now pick anonnegative simple function s < f. For r € (0,1), [fn > rs] = En is increasing in nand UnE, = Q. Tell why f frdu > f %z,frdu > rf sdu. Let n — © and show thata >rfsdu. Now explain why a >rf fdu. Since r is arbitrary, a > f fdu > a.31. Show that if f, g are nonnegative and measurable and a,b > 0, then| (af +bs)du =a fdu+b | gdp