320 CHAPTER 13. REPRESENTATION THEOREMS

Definition 13.2.2 Let (Ω,S ) be a measure space and let µ be a vector measuredefined on S . A subset, π(E), of S is called a partition of E if π(E) consists of finitelymany disjoint sets of S and ∪π(E) = E. Let

|µ|(E) = sup{ ∑F∈π(E)

∥µ(F)∥ : π(E) is a partition of E}.

|µ| is called the total variation of µ .

The next theorem may seem a little surprising. It states that, if finite, the total variationis a nonnegative measure.

Theorem 13.2.3 If |µ|(Ω) < ∞, then |µ| is a measure on S . Even if |µ|(Ω) =∞, |µ|(∪∞

i=1Ei) ≤ ∑∞i=1 |µ|(Ei) . That is |µ| is subadditive and |µ|(A) ≤ |µ|(B) whenever

A,B ∈S with A⊆ B.

Proof: Consider the last claim. Let a < |µ|(A) and let π (A) be a partition of A suchthat

a < ∑F∈π(A)

∥µ (F)∥ .

Then π (A)∪{B\A} is a partition of B and

|µ|(B)≥ ∑F∈π(A)

∥µ (F)∥+∥µ (B\A)∥> a.

Since this is true for all such a, it follows |µ|(B)≥ |µ|(A) as claimed.Let

{E j}∞

j=1 be a sequence of disjoint sets of S and let E∞ = ∪∞j=1E j. Then letting

a < |µ|(E∞) , it follows from the definition of total variation there exists a partition of E∞,π(E∞) = {A1, · · · ,An} such that a < ∑

ni=1 ∥µ(Ai)∥. Also,

Ai = ∪∞j=1Ai∩E j

and so by the triangle inequality, ∥µ(Ai)∥ ≤ ∑∞j=1 ∥µ(Ai ∩E j)∥. Therefore, by the above,

and either Fubini’s theorem or Lemma 1.11.3 on Page 28

a <n

∑i=1

≥∥µ(Ai)∥︷ ︸︸ ︷∞

∑j=1∥µ(Ai∩E j)∥=

∑j=1

n

∑i=1∥µ(Ai∩E j)∥ ≤

∑j=1|µ|(E j)

because{

Ai∩E j}n

i=1 is a partition of E j.Since a is arbitrary, this shows |µ|(∪∞

j=1E j) ≤ ∑∞j=1 |µ|(E j). If the sets, E j are not

disjoint, let F1 = E1 and if Fn has been chosen, let Fn+1 ≡ En+1 \∪ni=1Ei. Thus the sets, Fi

are disjoint and ∪∞i=1Fi = ∪∞

i=1Ei. Therefore,

|µ|(∪∞

j=1E j)= |µ|

(∪∞

j=1Fj)≤

∑j=1|µ|(Fj)≤

∑j=1|µ|(E j)

and proves |µ| is always subadditive as claimed regardless of whether |µ|(Ω)< ∞.

320 CHAPTER 13. REPRESENTATION THEOREMSDefinition 13.2.2 Le (Q,.%) be a measure space and let & be a vector measuredefined on SY. A subset, N(E), of S is called a partition of E if 1(E) consists of finitelymany disjoint sets of / and UN(E) = E. Let| |(E) = sup{ y? ||2(F)|| : @(E) is a partition of E}.Fen(E)|u| is called the total variation of U.The next theorem may seem a little surprising. It states that, if finite, the total variationis a nonnegative measure.Theorem 13.2.3 if |u\(Q) < ~, then |u| is a measure on -Y. Even if |u| (Q) =oo, |u| (U2, Ei) < Ly |u| (Ei). That is |u| is subadditive and ||(A) < |u| (B) wheneverA BES with ACB.Proof: Consider the last claim. Let a < |u| (A) and let 2 (A) be a partition of A suchthata< )' ||M(F)Fen(A)Then 7 (A) U {B\ A} is a partition of B andW\(B)> YY lu (F) || + ie (B\A)|| > aFen(A)Since this is true for all such a, it follows || (B) > |u| (A) as claimed.Let {E iit be a sequence of disjoint sets of .Y and let E.. = U7_,E;. Then lettinga < |p| (E..), it follows from the definition of total variation there exists a partition of E..,T(E.) = {A1,--- ,An} such that a < YL, || (A;)||. Also,Aj = Uj1Ai NE;and so by the triangle inequality, ||u(Ai)|| < L7_) ||¢(AiN£;)||. Therefore, by the above,and either Fubini’s theorem or Lemma 1.11.3 on Page 28> |qw(Ai)=O,a< PY maine) |=E Yang) \< Diwie;i=l j= j=li=lbecause {A;NE;}""_, is a partition of Ej.Since a is arbitrary, this shows wi(Ue eEj) < Le MIE i). If the sets, EZ; are notdisjoint, let F} = E; and if F,, has been chosen, let Fy4) = En44 VU" EB; Thus the sets, F;are disjoint and U;?_,F; = Uj, £;. Therefore,[e| (U712)) = || (UF1Fi) SMi=< ¥ |ul(E))j=l1Jand proves || is always subadditive as claimed regardless of whether || (Q) < ».