456 APPENDIX A. GREEN’S THEOREM FOR A JORDAN CURVE

By the dominated convergence theorem,

limδ→0

∫Iδ(Qx−Py)dm2 =

∫Ui

(Qx−Py)dm2

where m2 denotes two dimensional Lebesgue measure discussed earlier. Let ∂R denotethe boundary of R for R one of these regions of Lemma A.0.1 oriented as described. Letwδ (R)

2 denote

(max{Q(x) : x ∈ ∂R}−min{Q(x) : x ∈ ∂R})2

+(max{P(x) : x ∈ ∂R}−min{P(x) : x ∈ ∂R})2

By uniform continuity of P,Q on the compact set Ui ∪ J, if δ is small enough, wδ (R) < ε

for all R ∈Bδ . Then for R ∈Bδ , it follows from Theorem 5.2.1, for |∂R| denoting thelength of ∂R, ∣∣∣∣∫

∂Rf ·dγ

∣∣∣∣≤ (12

)wδ (R)(|∂R|)< ε (|∂R|) (1.1)

whenever δ is small enough. Always let δ be this small.Also since the line integrals cancel on shared edges

∑R∈Iδ

∫∂R

f ·dγ + ∑R∈Bδ

∫∂R

f ·dγ =∫

Jf ·dγ (1.2)

Consider the second sum on the left. From 1.1,∣∣∣∣∣ ∑R∈Bδ

∫∂R

f ·dγ

∣∣∣∣∣≤ ∑R∈Bδ

∣∣∣∣∫∂R

f ·dγ

∣∣∣∣≤ ε ∑R∈Bδ

(|∂R|)

Denote by JR the part of J which is contained in R ∈Bδ . Then the above sum equals

ε

(∑

R∈Bδ

(|JR|+ |∂Rδ |)

)=

(ε |J|+ ε ∑

R∈Bδ

|∂Rδ |)

where |∂Rδ | is the sum of the lengths of the straight edges of Rδ . This last sum is easyto estimate. Recall from A.0.1 there are no more than 4+ 128|J|

δof these border regions.

Furthermore, the sum of the lengths of all four edges of one of these is no more than 4δ

and so

∑R∈Bδ

|∂Rδ | ≤ 4(

4+128 |J|

δ

)4δ = 1024 |J|+64δ .

Thus∣∣∣∑R∈Bδ

∫∂R f ·dγ

∣∣∣ ≤ ε (1025 |J|+64δ ) Let εn → 0 and let δ n be the correspondingsequence of δ such that δ n→ 0 also. Hence

limn→∞

∣∣∣∣∣∣ ∑R∈Bδn

∫∂R

f ·dγ

∣∣∣∣∣∣= 0.

Then using Green’s theorem proved above for squares,∫J

f ·dγ = limn→∞

∑R∈Iδn

∫∂R

f ·dγ + limn→∞

∑R∈Bδn

∫∂R

f ·dγ

456 APPENDIX A. GREEN’S THEOREM FOR A JORDAN CURVEBy the dominated convergence theorem,tim | (Q.—R,)dma = I (Q.—P))dmswhere m denotes two dimensional Lebesgue measure discussed earlier. Let OR denotethe boundary of R for R one of these regions of Lemma A.0.1 oriented as described. Letwg (R)* denote(max {Q(x) :x € OR} —min{Q(x) :x € AR})*+ (max {P (x) :x € JR} —min{P(x):x € JR})By uniform continuity of P,Q on the compact set U; UJ, if 5 is small enough, ws (R) < €for all R€ @s. Then for R € Bs, it follows from Theorem 5.2.1, for |AR| denoting thelength of OR,[fay < (5) ws (R) (AR|) <€ (|AR}) (1.1)whenever 6 is small enough. Always let 6 be this small.Also since the line integrals cancel on shared edgesf-dy+ | f-d = [t-d 12Y etre, babar [har (1.2)Re45Consider the second sum on the left. From 1.1,»L [tear <b [false (|OR})REBs CBsDenote by Jr the part of J which is contained in R € 4s. Then the above sum equalse( y (al) = [evive y a)REBs REBswhere |OR5| is the sum of the lengths of the straight edges of Rs. This last sum is easyto estimate. Recall from A.0.1 there are no more than 4+ Rll of these border regions.Furthermore, the sum of the lengths of all four edges of one of these is no more than 46and so128 |Jyo \ARs| <4 (4+ ) 46 = 1024|J| +646.REBs 6Thus |Yrews loef-dy/ < €(1025|/| +6465) Let ¢, — 0 and let 5, be the correspondingsequence of 6 such that 6, > 0 also. Hencelim [ f-dy| =0.noo ot, OR YThen using Green’s theorem proved above for squares,f-dy=lim [ f-dy+ lim | f-d