260 CHAPTER 14. VECTOR VALUED FUNCTIONS OF ONE VARIABLE

Therefore, from (14.6),

ddt

(|r (t)−P 1|)+ddt

(|r (t)−P 0|) = 0

showing that |r (t)−P 1|+ |r (t)−P 0|=C for some constant C.This implies the curve ofintersection of the plane with the room is an ellipse having P 0 and P 1 as the foci.

14.2.3 Leibniz’s NotationLeibniz’s notation also generalizes routinely. For example, dy

dt = y′ (t) with other similarnotations holding.

14.3 Exercises1. Find the following limits if possible

(a) limx→0+

(|x|x ,sinx/x,cosx

)(b) limx→0+

(x|x| ,secx,ex

)(c) limx→4

(x2−16x+4 ,x+7, tan4x

5x

)(d) limx→∞

(x

1+x2 ,x2

1+x2 ,sinx2

x

)2. Find

limx→2

(x2−4x+2

,x2 +2x−1,x2−4x−2

).

3. Prove from the definition that limx→a ( 3√

x,x+1) = ( 3√

a,a+1) for all a ∈ R. Hint:You might want to use the formula for the difference of two cubes,

a3−b3 = (a−b)(a2 +ab+b2) .

4. Letr (t) =

(4+ t2,

√t2 +1t3, t3

)describe the position of an object in R3 as a function of t where t is measured inseconds and r (t) is measured in meters. Is the velocity of this object ever equal tozero? If so, find the value of t at which this occurs and the point in R3 at which thevelocity is zero.

5. Let r (t) =(sin2t, t2,2t +1

)for t ∈ [0,4]. Find a tangent line to the curve parame-

terized by r at the point r (2).

6. Let r (t)=(t,sin t2, t +1

)for t ∈ [0,5]. Find a tangent line to the curve parameterized

by r at the point r (2).

7. Let r (t) =(sin t, t2,cos

(t2))

for t ∈ [0,5]. Find a tangent line to the curve parame-terized by r at the point r (2).

260 CHAPTER 14. VECTOR VALUED FUNCTIONS OF ONE VARIABLETherefore, from (14.6),d© (In (¢)— Pil) + (In) Pol) =showing that |r (t) — Pi|+ |r (t) — Po| =C for some constant C.This implies the curve ofintersection of the plane with the room is an ellipse having Pp and P, as the foci.14.2.3 Leibniz’s NotationLeibniz’s notation also generalizes routinely. For example, ty = y’ (t) with other similarnotations holding.14.3. Exercises1. Find the following limits if possible[x](a) limy04 (2, sinx/x,cos:)(b) lim,—o+ (4 ,secx, e~ )(0) Timys4 (SS8,2-+7, 4")2 2‘ x Xx sinx(A) Timy ye (29.7%, )2. Find 5 2. x“ —4 4tim (<SS9? 42 —1, x >).3. Prove from the definition that lim, (\/x,x+ 1) = (W/a,a+1) for all a € R. Hint:You might want to use the formula for the difference of two cubes,a’ —b’ = (a—b) (a? +ab+b’).4. Letr(t)= (44°, VP + 13,15)describe the position of an object in R* as a function of t where t is measured inseconds and r(t) is measured in meters. Is the velocity of this object ever equal tozero? If so, find the value of ¢ at which this occurs and the point in R? at which thevelocity is zero.5. Let r(t) = (sin2r,1?,2t+1) fort € [0,4]. Find a tangent line to the curve parame-terized by r at the point r (2).6. Let r(t) = (t,sin¢?,t + 1) fort € [0,5]. Find a tangent line to the curve parameterizedby r at the point r (2).7. Let r(t) = (sin¢, rt? cos (t *)) for t € [0,5]. Find a tangent line to the curve parame-terized by r at the point r (2).