666 CHAPTER 33. BOUNDARY VALUE PROBLEMS, FOURIER SERIES

33. This problem is tedious but maybe it is better to do it all at once than to repeatseemingly endless virtually identical problems. In this problem, a is positive and b isa nonzero real number while n is a nonnegative integer. Find the real and imaginaryparts of a solution y to

y′′+2ay′+by = exp(

inπtL

)using the method of undetermined coefficients. Show that the real part is

2πL3ansin π

L nt−π2L2n2 cos π

L ntL4b2 +4π2L2a2n2−2π2L2bn2 +π4n4

and the imaginary part of the solution is(L4b−π2L2n2

)sin π

L nt−2πL3ancos π

L ntL4b2 +4π2L2a2n2−2π2L2bn2 +π4n4

Explain why the real part is a particular solution to

y′′+2ay′+by = cos(nπt

L

)and the imaginary part is a particular solution to

y′′+2ay′+by = sin(nπt

L

)In case n is 0, a solution is 1/b.

34. Using the above problem, describe the solution after a long time to the equation

y′′+2y′+2y = f (t)

where f (t) is a periodic function which has the following Fourier series. Note thatthe transient terms will disappear due to the fact that a = 1 is positive. Note thatwith the above problem, you could do many other examples in which a and b are notgiven as here.

(a) ∑∞n=1

1n2 cos

( nπt3

)+∑

∞n=1

11+n2 sin

( nπt3

)+3

(b) ∑∞n=1 e−n cos

( nπt2

)+∑

∞n=1

1n4 sin

( nπt2

)+1

(c) ∑∞n=1

1n3 cos

( nπt4

)+∑

∞n=1

1n3+1 sin

( nπt4

)−2

35. Suppose you have an undamped equation

y′′+4y = f (t)

where f is periodic. Suppose in the Fourier expansion of f (t) there is a nonzero termwhich is of the form bsin(2t) . Say it describes the transverse vibrations of a bridgein the center. What will likely happen to this bridge?

66633.34.35.CHAPTER 33. BOUNDARY VALUE PROBLEMS, FOURIER SERIESThis problem is tedious but maybe it is better to do it all at once than to repeatseemingly endless virtually identical problems. In this problem, a is positive and b isa nonzero real number while n is a nonnegative integer. Find the real and imaginaryparts of a solution y toTty" + 2ay' + by = exp (i)using the method of undetermined coefficients. Show that the real part is2aLansin Ent — nL? n? cos EntTAb2 + 47?12a2n2 — 27212 bn2 + 24n4and the imaginary part of the solution is(L*b — 1m Ln”) sin #nt — 2nL ancos EntDAb2 + 47?12.a2n2 — 22212 bn2 + 14n4Explain why the real part is a particular solution tonity” + 2ay' + by = cos ( r )and the imaginary part is a particular solution toy” + 2ay' + by = sin ()In case n is 0, a solution is 1/b.Using the above problem, describe the solution after a long time to the equationy" +2y'+2y = f(t)where f (t) is a periodic function which has the following Fourier series. Note thatthe transient terms will disappear due to the fact that a = 1 is positive. Note thatwith the above problem, you could do many other examples in which a and b are notgiven as here.(a) ye 5 COS (4H) +r Te sin (2%) +3n nitSuppose you have an undamped equationy’+4y= f(t)where f is periodic. Suppose in the Fourier expansion of f (t) there is a nonzero termwhich is of the form bsin (2r). Say it describes the transverse vibrations of a bridgein the center. What will likely happen to this bridge?