248 CHAPTER 10. NORMED LINEAR SPACES
10.1.2 Cauchy Sequences, Completeness
Of course it does not go the other way. For example, you could let xn = (−1)n and it has aconvergent subsequence but fails to converge. Here d (x,y) = |x− y| and the metric spaceis just R.
However, there is a kind of sequence for which it does go the other way. This is calleda Cauchy sequence.
Definition 10.1.15 {xn} is called a Cauchy sequence if for every ε > 0 there exists N suchthat if m,n≥ N, then d (xn,xm)< ε .
Now the major theorem about this is the following.
Theorem 10.1.16 Let {xn} be a Cauchy sequence. Then it converges if and only if anysubsequence converges.
Proof: =⇒ This was just done above.⇐= Suppose now that {xn} is a Cauchy sequence and limk→∞ xnk = x. Then there exists
N1 such that if k > N1, then d(xnk ,x
)< ε/2. From the definition of what it means to be
Cauchy, there exists N2 such that if m,n≥N2, then d (xm,xn)< ε/2. Let N ≥max(N1,N2).Then if k ≥ N, then nk ≥ N and so
d (x,xk)≤ d(x,xnk
)+d(xnk ,xk
)<
ε
2+
ε
2= ε (10.1)
It follows from the definition that limk→∞ xk = x. ■
Definition 10.1.17 A metric space is said to be complete if every Cauchy sequence con-verges.
Another nice thing to note is this.
Proposition 10.1.18 If {xn} is a sequence and if p is a limit point of the set S = ∪∞n=1 {xn}
then there is a subsequence{
xnk
}such that limk→∞ xnk = x.
Proof: By Theorem 10.1.7, there exists a sequence of distinct points of S denoted as{yk} such that none of them equal p and limk→∞ yk = p. Thus B(p,r) contains infinitelymany different points of the set D, this for every r. Let xn1 ∈ B(p,1) where n1 is the firstindex such that xn1 ∈ B(p,1). Suppose xn1 , · · · ,xnk have been chosen, the ni increasing andlet 1 > δ 1 > δ 2 > · · ·> δ k where xni ∈ B(p,δ i) . Then let
δ k+1 ≤min{
12k+1 ,d
(p,xn j
),δ j, j = 1,2 · · · ,k
}Let xnk+1 ∈ B(p,δ k+1) where nk+1 is the first index such that xnk+1 is contained B(p,δ k+1).Then limk→∞ xnk = p. ■
Another useful result is the following.
Lemma 10.1.19 Suppose xn→ x and yn→ y. Then d (xn,yn)→ d (x,y).