10.9. EXERCISES 283

12. Suppose K is a compact subset (If C is a set of open sets whose union containsK,(open cover) then there are finitely many sets of C whose union contains K.) of(X ,d) a metric space. Also let C be an open cover of K. Show that there exists δ > 0such that for all x ∈ K, B(x,δ ) is contained in a single set of C . This number iscalled a Lebesgue number. Hint: For each x ∈ K, there exists B(x,δ x) such that thisball is contained in a set of C . Now consider the balls

{B(

x, δ x2

)}x∈K

. Finitely

many of these cover K.{

B(

xi,δ xi2

)}n

i=1Now consider what happens if you let δ ≤

min{

δ xi2 , i = 1,2, · · · ,n

}. Explain why this works. You might draw a picture to help

get the idea.

13. Suppose C is a set of compact sets (A set is compact if every open cover admitsa finite subcover.) in a metric space (X ,d) and suppose that the intersection of ev-ery finite subset of C is nonempty. This is called the finite intersection property.Show that ∩C , the intersection of all sets of C is nonempty. This particular result isenormously important. Hint: You could let U denote the set

{KC : K ∈ C

}. If ∩C

is empty, then its complement is ∪U = X . Picking K ∈ C , it follows that U is anopen cover of K. Therefore, you would need to have

{KC

1 , · · · ,KCm}

is a cover of K.In other words,

K ⊆ ∪mi=1KC

i = (∩mi=1Ki)

C

Now what does this say about the intersection of K with these Ki?

14. Show that if f is continuous and defined on a compact set K in a metric space, thenit is uniformly continuous. Continuous means continuous at every point. Uniformlycontinuous means: For every ε > 0 there exists δ > 0 such that if d (x,y) < δ , thend ( f (x) , f (y)) < ε . The difference is that δ does not depend on x. Hint: Use theexistence of the Lebesgue number in Problem 12 to prove continuity on a compactset K implies uniform continuity on this set. Hint: Consider

C ≡{

f−1 (B( f (x) ,ε/2)) : x ∈ X}.

This is an open cover of X . Let δ be a Lebesgue number for this open cover. Sup-pose d (x, x̂)< δ . Then both x, x̂ are in B(x,δ ) and so both are in f−1

(B(

f (x̄) , ε

2

)).

Hence ρ ( f (x) , f (x̄)) < ε

2 and ρ ( f (x̂) , f (x̄)) < ε

2 . Now consider the triangle in-equality. Recall the usual definition of continuity. In metric space it is as follows:For (D,d) ,(Y,ρ) metric spaces, f : D→ Y is continuous at x ∈ D means that for allε > 0 there exists δ > 0 such that if d (y,x)< δ , then ρ ( f (x) , f (y))< ε . Continuityon D means continuity at every point of D.

15. The definition of compactness is that a set K is compact if and only if every opencover (collection of open sets whose union contains K) has a finite subset which isalso an open cover. Show that this is equivalent to saying that every open coverconsisting of balls has a finite subset which is also an open cover.

16. A set K in a metric space is said to be sequentially compact if whenever {xn} is asequence in K, there exists a subsequence which converges to a point of K. Show thatif K is compact, then it is sequentially compact. Hint: Explain why if x ∈ K, thenthere exist an open set Bx containing x which has xk for only finitely many values ofk. Then use compactness. This was shown in the chapter, but do your own proof ofthis part of it.

10.9.12.13.14.15.16.EXERCISES 283Suppose K is a compact subset (If @ is a set of open sets whose union containsK,(open cover) then there are finitely many sets of @ whose union contains K.) of(X,d) a metric space. Also let @ be an open cover of K. Show that there exists 6 > 0such that for all x € K, B(x, 6) is contained in a single set of @. This number iscalled a Lebesgue number. Hint: For each x € K, there exists B(x, 6,.) such that thisball is contained in a set of @. Now consider the balls {B (s. 5s) Kr FinitelyxEnmany of these cover K. {B (x: =) \ Now consider what happens if you let 6 <I=min { oy i=1,2,--- inh, Explain why this works. You might draw a picture to helpget the idea.Suppose @ is a set of compact sets (A set is compact if every open cover admitsa finite subcover.) in a metric space (X,d) and suppose that the intersection of ev-ery finite subset of @ is nonempty. This is called the finite intersection property.Show that N@, the intersection of all sets of @ is nonempty. This particular result isenormously important. Hint: You could let Y denote the set {K©: K € @}. If N@is empty, then its complement is UY = X. Picking K € @, it follows that Y is anopen cover of K. Therefore, you would need to have {Kf, ee KC is a cover of K.In other words,K CURAKE = (M21 Ki)Now what does this say about the intersection of K with these K;?Show that if f is continuous and defined on a compact set K in a metric space, thenit is uniformly continuous. Continuous means continuous at every point. Uniformlycontinuous means: For every € > 0 there exists 6 > 0 such that if d (x,y) < 6, thend(f (x), f(y)) < €. The difference is that 6 does not depend on x. Hint: Use theexistence of the Lebesgue number in Problem 12 to prove continuity on a compactset K implies uniform continuity on this set. Hint: Consider6 ={f' (B(f(x),€/2)):xEX}.This is an open cover of X. Let 6 be a Lebesgue number for this open cover. Sup-pose d (x,£) < 6. Then both x, £ are in B(x,6) and so both are in f~' (B(f (#),§)).Hence p (f (x), f (®)) < 5 and p(f(%),f(%)) < 5. Now consider the triangle in-equality. Recall the usual definition of continuity. In metric space it is as follows:For (D,d),(Y,p) metric spaces, f : D — Y is continuous at x € D means that for all€ > 0 there exists 6 > 0 such that if d(y,x) < 6, then p (f (x), f (y)) < €. Continuityon D means continuity at every point of D.The definition of compactness is that a set K is compact if and only if every opencover (collection of open sets whose union contains K) has a finite subset which isalso an open cover. Show that this is equivalent to saying that every open coverconsisting of balls has a finite subset which is also an open cover.A set K in a metric space is said to be sequentially compact if whenever {x,} is asequence in K, there exists a subsequence which converges to a point of K. Show thatif K is compact, then it is sequentially compact. Hint: Explain why if x € K, thenthere exist an open set B, containing x which has x; for only finitely many values ofk, Then use compactness. This was shown in the chapter, but do your own proof ofthis part of it.