380 CHAPTER 13. MATRICES AND THE INNER PRODUCT

must be Hermitian. Therefore, it is necessary that(σ 00 0

)(P QR S

)=

(σP σQ0 0

)=

(I σQ0 0

)is Hermitian. Then (

I σQ0 0

)=

(I 0

Q∗σ 0

)and so Q = 0.

Next,

A0︷ ︸︸ ︷V

(P QR S

)U∗

A︷ ︸︸ ︷UΣV ∗ =V

(Pσ 0Rσ 0

)V ∗ =V

(I 0

Rσ 0

)V ∗

is Hermitian. Therefore, also (I 0

Rσ 0

)is Hermitian. Thus R = 0 because(

I 0Rσ 0

)∗=

(I σ∗R∗

0 0

)

which requires Rσ = 0. Now multiply on right by σ−1 to find that R = 0.Use 13.37 and the second equation of 13.36 to write

A0︷ ︸︸ ︷V

(P QR S

)U∗

A︷ ︸︸ ︷UΣV ∗

A0︷ ︸︸ ︷V

(P QR S

)U∗ =

A0︷ ︸︸ ︷V

(P QR S

)U∗.

which implies (P QR S

)(σ 00 0

)(P QR S

)=

(P QR S

).

This yields from the above in which is was shown that R,Q are both 0(σ−1 0

0 S

)(σ 00 0

)(σ−1 0

0 S

)=

(σ−1 0

0 0

)(13.39)

=

(σ−1 0

0 S

). (13.40)

Therefore, S = 0 also and so

V ∗A0U ≡

(P QR S

)=

(σ−1 0

0 0

)

380 CHAPTER 13. MATRICES AND THE INNER PRODUCTmust be Hermitian. Therefore, it is necessary thatCo)Ee S)(8 P00 9)is Hermitian. ThenI oQ \ | I 00 0 } \ Oto 0and soQ=0.Next,AoA— -—\—v".P —> P IVv 2 \urtevav( PO © \yeey o \yR S§ Ro 0O Ro 0is Hermitian. Therefore, alsoI ORo 0Ois Hermitian. Thus R = 0 because1 0\ (17 ofpRo 0} \O0O 0which requires Ro = 0. Now multiply on right by o~! to find that R = 0.Use 13.37 and the second equation of 13.36 to writeAo Ao AoAv(t 0 )utarv( Cluav(t aiR S RS R SPO o 0 PQ\ (P@R S 0 0 RS} \R SJ]?This yields from the above in which is was shown that R, Q are both 0-1 —1 —l(° ales alee S) - (° ,) (13.39)0 S 0 O 0 S 0 Oo! 0= . 13.40( 0 S ( )Therefore, S = 0 also and so-1R Ss 0 Owhich implies