272 CHAPTER 10. MARKOV PROCESSES

17. Suppose B =

(α c∗

b A

)is an (n+ 1)× (n+ 1) Hermitian nonnegative matrix where

α is a scalar and A is n × n. Show that α must be real, c = b, and A = A∗, A isnonnegative, and that if α = 0, then b = 0. Otherwise, α > 0.

18. ↑If A is an n× n complex Hermitian and nonnegative matrix, show that there existsan upper triangular matrix B such that B∗B = A. Hint: Prove this by induction. Itis obviously true if n = 1. Now if you have an (n+ 1)× (n+ 1) Hermitian nonnegative

matrix, then from the above problem, it is of the form

(α2 αb∗

αb A

), α real.

19. ↑ Suppose A is a nonnegative Hermitian matrix (all eigenvalues are nonnegative) whichis partitioned as

A =

(A11 A12

A21 A22

)where A11, A22 are square matrices. Show that det (A) ≤ det (A11) det (A22). Hint:Use the above problem to factor A getting

A =

(B∗

11 0∗

B∗12 B∗

22

)(B11 B12

0 B22

)

Next argue that A11 = B∗11B11, A22 = B∗

12B12 +B∗22B22. Use the Cauchy Binet theo-

rem to argue that det (A22) = det (B∗12B12 +B∗

22B22) ≥ det (B∗22B22) . Then explain

why

det (A) = det (B∗11) det (B

∗22) det (B11) det (B22)

= det (B∗11B11) det (B

∗22B22)

20. ↑ Prove the inequality of Hadamard. If A is a Hermitian matrix which is nonnegative(all eigenvalues are nonnegative), then det (A) ≤

∏iAii.

27217.18.19.20.CHAPTER 10. MARKOV PROCESSES*acb Aa is a scalar and A is n x n. Show that a must be real, c=b, and A = A*,A isnonnegative, and that if a = 0, then b= 0. Otherwise, a > 0.Suppose B = is an (n+ 1) x (n+ 1) Hermitian nonnegative matrix wheretif A is an n x n complex Hermitian and nonnegative matrix, show that there existsan upper triangular matrix B such that B*B = A. Hint: Prove this by induction. Itis obviously true if nm = 1. Now if you have an (n + 1) x (n + 1) Hermitian nonnegative2 *a’ abmatrix, then from the above problem, it is of the form b A ,@ real.a+ Suppose A is a nonnegative Hermitian matrix (all eigenvalues are nonnegative) whichis partitioned asA= Air AigAg Adewhere A;1, Ag2 are square matrices. Show that det (A) < det (A11) det (Ag2). Hint:Use the above problem to factor A gettingA= Bi, 0* By, BigBin Boo 0 BagNext argue that Ai, = By, Bi, Aso = BY, Big + Be. Boo. Use the Cauchy Binet theo-rem to argue that det (Ag2) = det (BY, Bie + BjBo2) > det (B3,Boo). Then explainwhydet (A) = det (By,) det (B3,) det (B11) det (Boz)det (BY, Bit) det (B35 Bo2)+ Prove the inequality of Hadamard. If A is a Hermitian matrix which is nonnegative(all eigenvalues are nonnegative), then det (A) < [], Ai.