Chapter 12
Self Adjoint Operators
12.1 Simultaneous Diagonalization
Recall the following definition of what it means for a matrix to be diagonalizable.
Definition 12.1.1 Let A be an n× n matrix. It is said to be diagonalizable if there existsan invertible matrix S such that
S−1AS = D
where D is a diagonal matrix.
Also, here is a useful observation.
Observation 12.1.2 If A is an n×n matrix and AS = SD for D a diagonal matrix, theneach column of S is an eigenvector or else it is the zero vector. This follows from observingthat for sk the kth column of S and from the way we multiply matrices,
Ask = λksk
It is sometimes interesting to consider the problem of finding a single similarity trans-formation which will diagonalize all the matrices in some set.
Lemma 12.1.3 Let A be an n×n matrix and let B be an m×m matrix. Denote by C thematrix
C ≡
(A 0
0 B
).
Then C is diagonalizable if and only if both A and B are diagonalizable.
Proof: Suppose S−1A ASA = DA and S−1
B BSB = DB where DA and DB are diagonal
matrices. You should use block multiplication to verify that S ≡
(SA 0
0 SB
)is such that
S−1CS = DC , a diagonal matrix.Conversely, suppose C is diagonalized by S = (s1, · · · , sn+m) . Thus S has columns si.
For each of these columns, write in the form
si =
(xi
yi
)
where xi ∈ Fn and where yi ∈ Fm. The result is
S =
(S11 S12
S21 S22
)
where S11 is an n×n matrix and S22 is an m×m matrix. Then there is a diagonal matrix,D1 being n× n and D2 m×m such that
D = diag (λ1, · · · , λn+m) =
(D1 0
0 D2
)
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