Chapter 3
Determinants
3.1 Basic Techniques and Properties
Let A be an n × n matrix. The determinant of A, denoted as det (A) is a number. If thematrix is a 2×2 matrix, this number is very easy to find.
Definition 3.1.1 Let A =
(a b
c d
). Then
det (A) ≡ ad− cb.
The determinant is also often denoted by enclosing the matrix with two vertical lines. Thus
det
(a b
c d
)=
∣∣∣∣∣ a b
c d
∣∣∣∣∣ .Example 3.1.2 Find det
(2 4
−1 6
).
From the definition this is just (2) (6)− (−1) (4) = 16.Assuming the determinant has been defined for k × k matrices for k ≤ n − 1, it is now
time to define it for n× n matrices.
Definition 3.1.3 Let A = (aij) be an n×n matrix. Then a new matrix called the cofactormatrix, cof (A) is defined by cof (A) = (cij) where to obtain cij delete the ith row and thejth column of A, take the determinant of the (n− 1)× (n− 1) matrix which results, (This
is called the ijth minor of A. ) and then multiply this number by (−1)i+j
. To make theformulas easier to remember, cof (A)ij will denote the ijth entry of the cofactor matrix.
Now here is the definition of the determinant given recursively.
Theorem 3.1.4 Let A be an n× n matrix where n ≥ 2. Then
det (A) =
n∑j=1
aij cof (A)ij =
n∑i=1
aij cof (A)ij . (3.1)
The first formula consists of expanding the determinant along the ith row and the secondexpands the determinant along the jth column.
Note that for a n× n matrix, you will need n! terms to evaluate the determinant in thisway. If n = 10, this is 10! = 3, 628 , 800 terms. This is a lot of terms.
In addition to the difficulties just discussed, why is the determinant well defined? Whyshould you get the same thing when you expand along any row or column? I think youshould regard this claim that you always get the same answer by picking any row or columnwith considerable skepticism. It is incredible and not at all obvious. However, it requiresa little effort to establish it. This is done in the section on the theory of the determinantwhich follows.
Notwithstanding the difficulties involved in using the method of Laplace expansion,certain types of matrices are very easy to deal with.
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