94 CHAPTER 3. DETERMINANTS

3.3.4 Basic Properties of the Determinant

Definition 3.3.10 A vector, w, is a linear combination of the vectors {v1, · · · ,vr} ifthere exist scalars c1, · · · cr such that w =

∑rk=1 ckvk. This is the same as saying w ∈

span (v1, · · · ,vr) .

The following corollary is also of great use.

Corollary 3.3.11 Suppose A is an n × n matrix and some column (row) is a linear com-bination of r other columns (rows). Then det (A) = 0.

Proof: Let A =(

a1 · · · an

)be the columns of A and suppose the condition that

one column is a linear combination of r of the others is satisfied. Say ai =∑

j ̸=i cjaj . Thenby Corollary 3.3.9, det(A) =

det(

a1 · · ·∑

j ̸=i cjaj · · · an

)=∑j ̸=i

cj det(

a1 · · · aj · · · an

)= 0

because each of these determinants in the sum has two equal rows. ■Recall the following definition of matrix multiplication.

Definition 3.3.12 If A and B are n × n matrices, A = (aij) and B = (bij), AB = (cij)where cij ≡

∑nk=1 aikbkj .

One of the most important rules about determinants is that the determinant of a productequals the product of the determinants.

Theorem 3.3.13 Let A and B be n× n matrices. Then

det (AB) = det (A) det (B) .

Proof: Let cij be the ijth entry of AB. Then by Proposition 3.3.6, and the way wemultiply matrices,

det (AB) =∑

(k1,··· ,kn)

sgn (k1, · · · , kn) c1k1· · · cnkn

=∑

(k1,··· ,kn)

sgn (k1, · · · , kn)

(∑r1

a1r1br1k1

)· · ·

(∑rn

anrnbrnkn

)

=∑

(r1··· ,rn)

∑(k1,··· ,kn)

sgn (k1, · · · , kn) br1k1· · · brnkn

(a1r1 · · · anrn)

=∑

(r1··· ,rn)

sgn (r1 · · · rn) a1r1 · · · anrn det (B) = det (A) det (B) .■

The Binet Cauchy formula is a generalization of the theorem which says the determinantof a product is the product of the determinants. The situation is illustrated in the followingpicture where A,B are matrices.

B A

94 CHAPTER 3. DETERMINANTS3.3.4. Basic Properties of the DeterminantDefinition 3.3.10 A vector, w, is a linear combination of the vectors {v1,---,v,} ifthere exist scalars c,,---c, such that w = pe Chevy. This is the same as saying w €span (V1,°°+,V,).The following corollary is also of great use.Corollary 3.3.11 Suppose A is ann xn matrix and some column (row) is a linear com-bination of r other columns (rows). Then det (A) = 0.Proof: Let A = ( al -t: ap ) be the columns of A and suppose the condition thatone column is a linear combination of r of the others is satisfied. Say a; = )),,; ¢jaj. Thenby Corollary 3.3.9, det(A) =det ( ay tee ei CABS tee an ) = doejdet (ar er: a, ) =0J#ibecause each of these determinants in the sum has two equal rows.Recall the following definition of matrix multiplication.Definition 3.3.12 If A and B aren x n matrices, A = (a;;) and B = (b;), AB = (ci;)where Ci; = op—1 Ainbdrj-One of the most important rules about determinants is that the determinant of a productequals the product of the determinants.Theorem 3.3.13 Let A and B ben x n matrices. Thendet (AB) = det (A) det (B).Proof: Let c;; be the ij’” entry of AB. Then by Proposition 3.3.6, and the way wemultiply matrices,det(AB) = — S> sen(ki,-++ Rn) Ctky “Cnty(k1,+++ kn)S- sgn (ki, tee kin) (= Gir, bas ote (= anrn bat(kis skn)= S- S- sgn (ki, ++: Kin) Drs ky +! On ken (air, ++ Onr, )(ris Tn) (kis skn)= S- sgn (11 +++ Tn) Air, ++ Anr, det (B) = det (A) det (B)(ris Tn)The Binet Cauchy formula is a generalization of the theorem which says the determinantof a product is the product of the determinants. The situation is illustrated in the followingpicture where A, B are matrices.