1182 CHAPTER 34. GELFAND TRIPLES AND RELATED STUFF

Consider ⟨Bgp−B

(k

∑i=1

⟨Bgp,ei

⟩ei

),gp−

k

∑i=1

⟨Bgp,ei

⟩ei

⟩If p ∈ (nk,nk+1) , then the above equals zero which implies

Bgp =k

∑i=1

⟨Bgp,ei

⟩Bei

On the other hand, suppose gp = gnk+1 for some nk+1 and so, from the construction, gnk+1 =gp ∈ span(e1, · · · ,ek+1) and therefore,

gp =k+1

∑j=1

a je j

which requires easily that

Bgp =k+1

∑i=1

⟨Bgp,ei

⟩Bei,

the above holding for all k large enough. To see this last claim, note that the coefficients ofBg=∑

mj=1 a jBe j are required to be a j =

⟨Bg,e j

⟩and from the construction,

⟨Bei,e j

⟩= δ i j.

Thus if the upper limit is increased beyond what is needed, the new terms are all zero. Itfollows that for any x ∈ span({gk}∞

k=1) , (finite linear combination of vectors in {gk}∞

k=1)

Bx =∞

∑i=1⟨Bx,ei⟩Bei (34.4.18)

because for all k large enough,

Bx =k

∑i=1⟨Bx,ei⟩Bei

Also note that for such x ∈ span({

g j}∞

j=1

),

⟨Bx,x⟩ =

⟨k

∑i=1⟨Bx,ei⟩Bei,x

⟩=

k

∑i=1⟨Bx,ei⟩⟨Bx,ei⟩

=k

∑i=1|⟨Bx,ei⟩|2 =

∑i=1|⟨Bx,ei⟩|2

Now for x arbitrary, let xk→ x in W where xk ∈ span({gk}∞

k=1) . Then by Fatou’s lemma,

∑i=1|⟨Bx,ei⟩|2 ≤ lim inf

k→∞

∑i=1|⟨Bxk,ei⟩|2

= lim infk→∞

⟨Bxk,xk⟩= ⟨Bx,x⟩ (34.4.19)

≤ ∥Bx∥W ′ ∥x∥W ≤ ∥B∥∥x∥2W

1182 CHAPTER 34. GELFAND TRIPLES AND RELATED STUFFConsideri=lk k(2, —B (2 (ene) 8p — )) (B8psei) “|i=lIf p € (ng, Ng41), then the above equals zero which implieskBgp = » (Bgp, ei) Beii=lOn the other hand, suppose gp = gn, a for some nz, and so, from the construction, gy, weSp € span (e1,--- ,ex41) and therefore,k+lSp = » ajejj=lwhich requires easily thatk+lBgy = Y- (Bgp,ei) Bei,i=lthe above holding for all k large enough. To see this last claim, note that the coefficients ofBg= ye , ajBe; are required to be a; = (Bg, e;) and from the construction, (Be;, e;) = 6j;.Thus if the upper limit is increased beyond what is needed, the new terms are all zero. Itfollows that for any x € span ({g,};_,), (finite linear combination of vectors in {g,};_1)Bx=Ms(Bx, e;) Be; (34.4.18)llianbecause for all k large enough,M=Bx= ) (Bx, e;) Be;icovyNYSAlso note that for such x € span ({ gi}P)nu(Bx,x) =—~k k¥ (Be) Bes) = yi ( (Bx, e;) (Bx, e;)i=l i=l|(Bx,¢)|?Ms|(Bx,¢))|? =1 iIM=1Now for x arbitrary, let x, — x in W where x; € span ({gx};_,). Then by Fatou’s lemma,Y | (Bx,ei)|> << lim inf Y° | (Bxx, e7)?i=l k-y00 j== lim inf (Bx, Xk) = (Bx, x) (34.4.19)— oo2< |[Bxllwe lll < |B Melly