34.4. THE IMPLICIT CASE 1189

Thus, if sn→ t,sn ∈ D, Fatou’s lemma implies

⟨Bu,u⟩(t) = ⟨B(u(t)) ,u(t)⟩=∞

∑k=1|⟨Bu(t) ,ei⟩|2

≤ lim infn→∞

∑k=1|⟨Bu(sn) ,ei⟩|2 ≤C (∥Y∥K′ ,∥u∥K)

and sosupt∈NC⟨Bu,u⟩(t) = sup

t∈NC⟨B(u(t)) ,u(t)⟩ ≤C (∥Y∥K′ ,∥u∥K)

It only remains to verify the claim about weak continuity.Consider now the claim that t→ Bu(t) is weakly continuous on NC. Letting v ∈V,s ∈

NC,

limt→s⟨Bu(t) ,v⟩= ⟨Bu(s) ,v⟩= ⟨Bu(s) ,v⟩ (34.4.24)

The limit follows from the formula 34.4.22 which implies t→ Bu(t) is continuous into V ′.Now for t ∈ NC,

∥Bu(t)∥= sup∥v∥≤1

|⟨Bu(t) ,v⟩| ≤ ⟨Bv,v⟩1/2 ⟨Bu(t) ,u(t)⟩1/2

which was shown to be bounded for t,s ∈ NC. Now let w ∈W . Then

|⟨Bu(t) ,w⟩−⟨Bu(s) ,w⟩| ≤ |⟨Bu(t)−Bu(s) ,w− v⟩|+ |⟨Bu(t)−Bu(s) ,v⟩|

Then the first term is less than ε if v is close enough to w and the second converges to 0 so34.4.24 holds for all v ∈W and so this shows the weak continuity on NC.

Now pick t ∈ D, the union of all the mesh points. Then for all k large enough, t ∈Pk.Say t = tm. From Lemma 34.4.4,

−m−1

∑j=0

⟨B(u(t j+1

)−u(t j)

),(u(t j+1

)−u(t j)

)⟩=

⟨Bu(tm) ,u(tm)⟩−⟨Bu0,u0⟩−2m−1

∑j=0

∫ t j+1

t j

⟨Y (r) ,urk (r)⟩dr

Thus, ⟨Bu(tm) ,u(tm)⟩ is constant for all k large enough and the integral term converges to∫ tm

0⟨Y (r) ,u(r)⟩dr

It follows that the term on the left does converge to something as k→ ∞. It just remains toconsider what it does converge to. However, from the equation solved by u,

Bu(t j+1

)−Bu(t j) =

∫ t j+1

t j

Y (r)dr

34.4, THE IMPLICIT CASE 1189Thus, if s, — t,s, € D, Fatou’s lemma implies(Buu) (t) = (B(u(0)) u()) = ¥ MBule) ed)?IAtim inf, Y° |(Bu (sp) .€7)[? <C (lela)k=1and sosup (Bu,u) (t) = Sup (B(u(t)) u(t)) <C([I¥ lle lalla)It only remains to verify the claim about weak continuity.Consider now the claim that t +> Bu(t) is weakly continuous on N©. Letting v € V,s €NS,lim (Bu (t) ,v) = (Bu(s),v) = (Bu(s) ,v) (34.4.24)tsThe limit follows from the formula 34.4.22 which implies t + Bu (t) is continuous into V’.Now fort € N°,||Bu (t)|| = sup | (Bu (t) ,v)| < (Bv,v)'/? (Bu(t) u(r)!which was shown to be bounded for t,s € N©. Now let w € W. Then| (Bu (t) ,w) — (Bu(s),w)| < |(Bu(t) — Bu(s) ,w—v)| + |(Bu(t) — Bu(s) ,v)|Then the first term is less than € if v is close enough to w and the second converges to 0 so34.4.24 holds for all v € W and so this shows the weak continuity on N°. §jNow pick t € D, the union of all the mesh points. Then for all k large enough, t € Px.Say t =t,. From Lemma 34.4.4,m—1—)) (B(u(th1) — 4). (utr) —u(ty))) =Jj=0m—1 til(Bu (tm) ,1 (tm)) — (Buo,uo) —2 y | (Y (r) ,ul (r) drjoo %4iThus, (Bu (tm) ,u(tm)) is constant for all k large enough and the integral term converges to[vr o.unyarIt follows that the term on the left does converge to something as k — o. It just remains toconsider what it does converge to. However, from the equation solved by u,Bu (tj+1) — Bu (t;) = f° Y(r) drtj