43.1. SOME STANDARD TECHNIQUES IN EVOLUTION EQUATIONS 1421
provided n is large enough. This follows from continuity of translation in Lp with Lebesguemeasure. Since ε > 0 is arbitrary, it follows fn → f̂ in Lp (R;V ) . Similarly, fn → f inL2 (R;H). This follows because p ≥ 2 and the norm in V and norm in H are related by|x|H ≤C ||x||V for some constant, C. Now
f̂ (t) =
Ψ(t) f (t) if t ∈ [0,T ] ,Ψ(t) f (2T − t) if t ∈ [T,2T ] ,Ψ(t) f (−t) if t ∈ [0,T ] ,0 if t /∈ [−T,2T ] .
An easy modification of the argument of Lemma 43.1.13 yields
f̂ ′ (t) =
Ψ′ (t) f (t)+Ψ(y) f ′ (t) if t ∈ [0,T ] ,Ψ′ (t) f (2T − t)−Ψ(t) f ′ (2T − t) if t ∈ [T,2T ] ,Ψ′ (t) f (−t)−Ψ(t) f ′ (−t) if t ∈ [−T,0] ,0 if t /∈ [−T,2T ] .
.
Recall
fn (t) =∫ 1/n
−1/nf̂ (t− s)φ n (s)ds =
∫R
f̂ (t− s)φ n (s)ds
=∫R
f̂ (s)φ n (t− s)ds.
Therefore,
f ′n (t) =∫R
f̂ (s)φ′n (t− s)ds =
∫ 2T+ 1n
−T− 1n
f̂ (s)φ′n (t− s)ds
=∫ 2T+ 1
n
−T− 1n
f̂ ′ (s)φ n (t− s)ds =∫R
f̂ ′ (s)φ n (t− s)ds
=∫R
f̂ ′ (t− s)φ n (s)ds =∫ 1/n
−1/nf̂ ′ (t− s)φ n (s)ds
and it follows from the first line above that f ′n is continuous with values in V for all t ∈ R.Also note that both f ′n and fn equal zero if t /∈ [−T,2T ] whenever n is large enough. Exactlysimilar reasoning to the above shows that f ′n→ f̂ ′ in Lp′ (R;V ′) .
Now let φ ∈C∞c (0,T ) .∫
R| fn (t)|2H φ
′ (t)dt =∫R( fn (t) , fn (t))H φ
′ (t)dt (43.1.7)
=−∫R
2(
f ′n (t) , fn (t))
φ (t)dt = −∫R
2〈
f ′n (t) , fn (t)〉
φ (t)dt
Now ∣∣∣∣∫R 〈 f ′n (t) , fn (t)〉
φ (t)dt−∫R
〈f ′ (t) , f (t)
〉φ (t)dt
∣∣∣∣≤
∫R
(∣∣〈 f ′n (t)− f ′ (t) , fn (t)〉∣∣+ ∣∣〈 f ′ (t) , fn (t)− f (t)
〉∣∣)φ (t)dt.