1518 CHAPTER 46. SOBOLEV SPACES ON MANIFOLDS

This works because from the definition of γ on C∞(Ω)

and continuity of the map estab-lished above, γ and

(H−1

i

)∗commute and so

γRg ≡l

∑i=1

γ(H−1

i)∗

Rh∗i (ψ ig)

=l

∑i=1

(H−1

i)∗

γRh∗i (ψ ig)

=l

∑i=1

(H−1

i)∗h∗i (ψ ig) = g.

This proves the following theorem about the trace.

Theorem 46.2.2 Let Ω ∈ Cm−1,1. Then there exists a constant, C independent of u ∈W m,p (Ω) and a continuous linear map, γ : W m,p (Ω)→W m− 1

p ,p (∂Ω) such that 46.2.3holds. This map satisfies γu(x) = u(x) for all u ∈C∞

(Ω)

and γ is onto. In the case where

m = 1, there exists a continuous linear map, R : W 1− 1p ,p (∂Ω)→W 1,p (Ω) which has the

property that γRg = g for all g ∈W 1− 1p ,p (∂Ω).

Of course more can be proved but this is all to be presented here.

1518 CHAPTER 46. SOBOLEV SPACES ON MANIFOLDSThis works because from the definition of y on C® (Q) and continuity of the map estab-lished above, y and (H;')" commute and soyRg y (H; ') "Rh; (y;g)llM-(H;')° yRh; (y;g)IM-llmn(H;!) "hi (Wig) = 8.IM-This proves the following theorem about the trace.Theorem 46.2.2 Let Q€C”—!|!. Then there exists a constant, C independent of u €Ww"? (Q) and a continuous linear map, y : W""? (Q) > wry? (OQ) such that 46.2.3holds. This map satisfies yu (x) = u(x) for all u € C* (Q) and y is onto. In the case where1m = 1, there exists a continuous linear map, R: W'?’? (8Q) —> W'? (Q) which has the1property that yRg = g forall g € wip? (AQ).Of course more can be proved but this is all to be presented here.