51.5. ZEROS OF AN ANALYTIC FUNCTION 1629

8. Suppose that u(w) is a given real continuous function defined on ∂B(0,R) and definef (z) for |z|< R by 51.4.17. Show that f , so defined is analytic. Explain why u givenin 51.4.18 is harmonic. Show that

limr→R−

u(reiα)= u

(Reiα) .

Thus u is a harmonic function which approaches a given function on the boundaryand is therefore, a solution to the Dirichlet problem.

9. Suppose f (z) = ∑∞k=0 ak (z− z0)

k for all |z− z0|< R. Show that

f ′ (z) =∞

∑k=0

akk (z− z0)k−1

for all |z− z0| < R. Hint: Let fn (z) be a partial sum of f . Show that f ′n convergesuniformly to some function, g on |z− z0| ≤ r for any r < R. Now use the Cauchyintegral formula for a function and its derivative to identify g with f ′.

10. Use Problem 9 to find the exact value of ∑∞k=0 k2

( 13

)k.

11. Prove the binomial formula,

(1+ z)α =∞

∑n=0

n

)zn

where (α

n

)≡ α · · ·(α−n+1)

n!.

Can this be used to give a proof of the binomial formula,

(a+b)n =n

∑k=0

(nk

)an−kbk?

Explain.

12. Suppose f is analytic on B(z0,r) and continuous on B(z0,r) and | f (z)| ≤ M onB(z0,r). Show that then

∣∣∣ f (n) (a)∣∣∣≤ Mn!rn .

51.5 Zeros Of An Analytic FunctionIn this section we give a very surprising property of analytic functions which is in starkcontrast to what takes place for functions of a real variable.

Definition 51.5.1 A region is a connected open set.

It turns out the zeros of an analytic function which is not constant on some regioncannot have a limit point. This is also a good time to define the order of a zero.

51.5.10.11.12.ZEROS OF AN ANALYTIC FUNCTION 1629. Suppose that u(w) is a given real continuous function defined on 0B (0, R) and definef (z) for |z| < R by 51.4.17. Show that f, so defined is analytic. Explain why u givenin 51.4.18 is harmonic. Show that: ia\ _ iajim u (re ) =u(Re ).Thus uw is a harmonic function which approaches a given function on the boundaryand is therefore, a solution to the Dirichlet problem.Suppose f (z) = Y2_9 ax (z—zo)* for all |z— zo| < R. Show thatf (2) = YLak(z—2)*"k=0for all |z—zo| < R. Hint: Let f(z) be a partial sum of f. Show that f/ convergesuniformly to some function, g on |z—zo| < r for any r < R. Now use the Cauchyintegral formula for a function and its derivative to identify g with f’.Use Problem 9 to find the exact value of £29k? (4).Prove the binomial formula,(1+z)%= y (“Jen=0(*) _ @--(@=nt1)Can this be used to give a proof of the binomial formula,(a+b)" = y: (i) al pkk=0whereExplain.Suppose f is analytic on B(zo,r) and continuous on B(zo,r) and |f(z)| <M onB(zo,r). Show that then ir (a)| < Mnyn51.5 Zeros Of An Analytic FunctionIn this section we give a very surprising property of analytic functions which is in starkcontrast to what takes place for functions of a real variable.Definition 51.5.1 A region is a connected open set.It turns out the zeros of an analytic function which is not constant on some regioncannot have a limit point. This is also a good time to define the order of a zero.