2182 CHAPTER 64. WIENER PROCESSES

= limk→∞

E

(nk

∏j=1

exp(

i(

λ(X(s,t),g j

)L2 +µ

(X(r,s),g j

)L2

)ξ j

))

= limk→∞

nk

∏j=1

E(

exp(

i(

λ(X(s,t),g j

)L2 +µ

(X(r,s),g j

)L2

)ξ j

))

= limk→∞

nk

∏j=1

exp(−1

2(λX(s,t)+µX(r,s),g j

)2L2

)

= limk→∞

exp

(−1

2

nk

∑j=1

(λX(s,t)+µX(r,s),g j

)2L2

)

= exp

(−1

2

∑j=1

(λX(s,t)+µX(r,s),g j

)2L2

)= exp

(−1

2

∥∥λX(s,t)+µX(r,s)∥∥2

L2

)

= exp(−1

2

2∥∥X(s,t)∥∥2

L2 +µ2∥∥X(r,s)

∥∥2L2

])because the functions λX(s,t),µX(r,s) are orthogonal. Then this equals

= exp(−1

2

2 (t− s)+µ2 (s− r)

])

= exp(−1

2(t− s)λ

2)

exp(−1

2(s− r)µ

2)

which equals 64.1.2 and this shows the increments are independent. Obviously, this sameargument shows this holds for any finite set of disjoint increments.

From the definition, if t > s

W (t− s) =∞

∑k=1

(X(0,t−s),gk

)L2 ξ k

while

W (t)−W (s) =∞

∑k=1

(X(s,t),gk

)L2 ξ k.

Then the same argument given above involving the characteristic function to show W (t)is normally distributed shows both of these random variables are normally distributed withmean 0 and variance t− s because they have the same characteristic function.

2182 CHAPTER 64. WIENER PROCESSES= lmE (Tes (i @ (2s) si) p +U (2s)-8/) 2) 2)k-00 i]Nk= lim ITé (exp (i (2 (2s) +81) p +p (Zivs)-8i) 2) é,))k-y00 5= lim [Te (-5 (A251) +H 2X r5)s gi) :)K-00 5TMs1 2= Him exp (- 2} (A 2st) + UZ (5) ’ 8i) :)= oo(-oeoo 1Li Xs.) bn) (-; A su FHA rs li)1= exp (-5 [2 I| 2s.2) i + ue | %lh}because the functions NX s4)s HZ ys) are orthogonal. Then this equals= exp (-3 0-9) +2(6-n])=exp (—5 1-9) 4) exp (5 6-928)which equals 64.1.2 and this shows the increments are independent. Obviously, this sameargument shows this holds for any finite set of disjoint increments.From the definition, if t > sMsW (t—s) = (2ior—s)>8k) 2 FkkwhileMsW (t)-—W(s) = (2is)s8k) 72 Sek=1Then the same argument given above involving the characteristic function to show W (fr)is normally distributed shows both of these random variables are normally distributed withmean 0 and variance t — s because they have the same characteristic function.