2226 CHAPTER 64. WIENER PROCESSES

Thus, this has shown that for all A ∈Fs,∫A

E((W (t) ,h)2 |Fs

)dP−

∫A(W (s) ,h)2 dP

= P(A)(t− s)(Qh,h) =∫

A(t− s)(Qh,h)dP

and since A ∈Fs is arbitrary, this proves

E((W (t) ,h)2− t (Qh,h) |Fs

)= (W (s) ,h)2− s(Qh,h)

This proves one half of the theorem.Next suppose both {W (t)} and

{(W (t) ,h)2− t (Qh,h)

}are martingales for any h∈H.

It follows that both {(W (t) ,h)} and{(W (t) ,h)2− t (Qh,h)

}are martingales also. There-

fore, by Levy’s theorem, Theorem 63.8.5, {(W (t) ,h)} is a Wiener process with the prop-erty that its variance at t equals (Qh,h) t instead of t. Thus the time increments are normaland independent. I need to verify that {W (t)} is a Q Wiener process. One of the thingswhich needs to be shown is that

E ((W (t)−W (s) ,h1)(W (t)−W (s) ,h2)) = (Qh1,h2)(t− s) . (64.6.41)

I have just shownE((W (t)−W (s) ,h)2

)= (t− s)(Qh,h) (64.6.42)

which follows from Levy’s theorem which concludes {(W (t) ,h)} is a Wiener process.Therefore,

E ((W (t)−W (s) ,h1 +h2)(W (t)−W (s) ,h2 +h1))

= (Q(h1 +h2) ,(h1 +h2))(t− s)

Now using 64.6.42, it follows from this that

E ((W (t)−W (s) ,h1)(W (t)−W (s) ,h2)) = (Qh1,h2)(t− s)

which shows 64.6.41. This completes the proof.

2226 CHAPTER 64. WIENER PROCESSESThus, this has shown that for all A € F,,fe (ov@.m? a) ar— [ ws) ,mearA A= P(A)(r~s)(Qh.h) = | (3) (Oh,h)aPand since A € .F, is arbitrary, this provesE ((W(0),h)” —1(Oh,h) Fs) = (W (8) h)” ~9(Qh,h)This proves one half of the theorem.Next suppose both {W (rt) } and {(w (t) nh)” —t(Qh, n)} are martingales for any h € H.It follows that both {(W (t) ,/)} and {(w (t),h)? —t (Qh,h) } are martingales also. There-fore, by Levy’s theorem, Theorem 63.8.5, {(W (t) ,4)} is a Wiener process with the prop-erty that its variance at t equals (Qh,h)t instead of t. Thus the time increments are normaland independent. I need to verify that {W (t)} is a Q@ Wiener process. One of the thingswhich needs to be shown is thatE (W(t) —W(s).h1) (W(t) —W (8) .A2)) = (Ohi sha) (15). (64.6.41)I have just shownE ((w (1) —W(s) :n)?) = (t—s)(Qh,h) (64.6.42)which follows from Levy’s theorem which concludes {(W (t),4)} is a Wiener process.Therefore,E ((W (t) —W (s) 41 +h) (W(t) —W (s) ho +h1))= (Q(hy+h2), (hi +h2))(t—s)Now using 64.6.42, it follows from this thatE ((W (t) —W(s) 1) (W (t) —W (s) ,A2)) = (Qh, he) (t —)which shows 64.6.41. This completes the proof.