2262 CHAPTER 65. STOCHASTIC INTEGRATION

It follows one can consider ∫ T

aLΦdW.

Assume to begin with that Φ∈L2([a,T ]×Ω;L2

(Q1/2U,H

)). Next recall the situation

in which the definition of the integral is considered.

U↓ Q1/2

U1 ⊇ JQ1/2U J←1−1

Q1/2U

Φn ↘ ↓ Φ

H

Letting {Φn} be an approximating sequence of elementary functions satisfying

E(∫ T

a

∣∣∣∣Φn−Φ◦ J−1∣∣∣∣2L2(JQ1/2U,H) dt

)→ 0,

it is also the case that

E(∫ T

a

∣∣∣∣LΦn−LΦ◦ J−1∣∣∣∣2L2(JQ1/2U,H1)

dt)→ 0

By the definition of the integral, for each t∫ t

aLΦdW = lim

n→∞

∫ t

aLΦndW = lim

n→∞L∫ t

aΦndW

= L limn→∞

∫ t

aΦndW = L

∫ t

aΦdW

The second equality is obvious for elementary functions.Now consider the case where Φ is only stochastically square integrable so that all is

known is that

P([∫ T

a||Φ||2

L2(Q1/2U,H) dt < ∞

])= 1.

Then define τn as above

τn ≡ inf{

t :∫ t

a||Φ||2

L2(Q1/2U,H) dt ≥ n}

This sequence of stopping times works for LΦ also. Recall there were two conditions thesequence of stopping times needed to satisfy. The first is obvious. Here is why the secondholds.∫ T

a

∣∣∣∣X[a,τn]LΦ∣∣∣∣2

L2(Q1/2U,H1)dt ≤ ||L||2

∫ T

a

∣∣∣∣X[a,τn]Φ∣∣∣∣2

L2(Q1/2U,H) dt

= ||L||2∫

τn

a||Φ||2

L2(Q1/2U,H) dt ≤ ||L||2 n

2262 CHAPTER 65. STOCHASTIC INTEGRATIONIt follows one can consider r/ L®dW.aAssume to begin with that ® € L? ([a,T] x Q;.Z (Q'/?U,H)) . Next recall the situationin which the definition of the integral is considered.UL Qi?U; DvJo'?u & o!/2u1—®, \, + ®HLetting {®,,} be an approximating sequence of elementary functions satisfyingT—1))2E (/ ]®, Go IfE yoru) ar) +0,it is also the case thatTe(/ ||L®, —L@oJ™!a2L;(7Q"/2U,H)) ar) 70By the definition of the integral, for each tt t ‘t| L®dW = lim | L®,dW = lim 1 | @,dWaa ne Jaq n—yoot tLim, | o,dw =1 | dWa an—»ooThe second equality is obvious for elementary functions.Now consider the case where ® is only stochastically square integrable so that all isknown is that rP / fap) 2 dt < ~|) = 1.(| a | II'A(o12u.H)tT = inf r:[ ®||7 an}n { , | IA(o12u.H)This sequence of stopping times works for L® also. Recall there were two conditions thesequence of stopping times needed to satisfy. The first is obvious. Here is why the secondholds.Tr 2| | | %a,t,,LP| ‘a (o1ru sn) dtThen define T, as aboveIATWAP [UI Pies PllescoreuwTn2 2 2= (LIP [Ula (oveuny dt SILI