2278 CHAPTER 66. THE INTEGRAL∫ t

0 (Y,dM)H

Definition 66.0.7 Let G denote those functions Y which are adapted and have the propertythat for each p,

limn→∞

E(∫ T

0∥Y −Y n∥2

H d [M]τ p

)= 0

for some sequence Y n of elementary functions for which ∥Y n (t)∥M∗ ∈ L2 (Ω) for each t.Here d [M]τ p signifies the Lebesgue Stieltjes measure determined by the increasing functiont→ [Mτ p ] (t). Let Mτ p be an L2 martingale. Recall that τ p is just a localizing sequence forthe local martingale M.

It is not known whether this increasing function is absolutely continuous.

Definition 66.0.8 Let Y ∈ G . Then∫ t

0(Y,dMτ p)≡ lim

n→∞

∫ t

0(Y n,dMτ p) in L2 (Ω)

For example, suppose Y is a bounded continuous process having values in H. Then youcould look at the left step functions

Y n (t)≡mn−1

∑i=0

Y (ti)X[ti,ti+1) (t)

The Y n would converge to Y pointwise on [0,T ] for each ω and these Y n are bounded. Infact, in this case, these converge uniformly to Y on [0,T ]. Thus this is an example of thesituation in the above definition. In this case, the integrand would be bounded by C forsome C and

E(∫ T

0Cd [M]τ p

)= E

([M]τ p (T )

)= E

(∥Mτ p (T )∥2

)< ∞

by assumption. Hence, by the dominated convergence theorem,

limn→∞

E(∫ T

0∥Y −Y n∥2

H d [M]τ p

)= 0.

What if [M]τ p were bounded and absolutely continuous with respect to Lebesgue mea-sure? This could be the case if you had τ p a stopping time of the form

τ p = inf{t : [M] (t)> p}

Then if Y ∈ L2 ([0,T ]×Ω,H) , and progressively measurable there are left step functionswhich converge to Y in L2 ([0,T ]×Ω,H) . Say d [Mτ p ] = k (t,ω)dm where k is bounded.Then

E(∫ T

0∥Y −Y n∥2

H d [M]τ p

)= E

(∫ T

0∥Y −Y n∥2

H kdt)→ 0

2278 CHAPTER 66. THE INTEGRAL {\ (Y,dM),,Definition 66.0.7 Let Y denote those functions Y which are adapted and have the propertythat for each p,T: _ ypnyy2 Tp \ _tim ( [|v -Y"\jyaia*) =ofor some sequence Y" of elementary functions for which \|¥" (t)||M* € L? (Q) for each t.Here d|M]"° signifies the Lebesgue Stieltjes measure determined by the increasing functiont + [M*] (t). Let M*? be an L? martingale. Recall that Tp is just a localizing sequence forthe local martingale M.It is not known whether this increasing function is absolutely continuous.Definition 66.0.8 Let Y € Y. Thenot et/ (Y,dM) = lim | (Y",dM*) in L? (Q)0 nee JOFor example, suppose Y is a bounded continuous process having values in H. Then youcould look at the left step functionsmn—1Y"(t)= » Y (ti) Pinas) 0)The Y” would converge to Y pointwise on [0,7] for each @ and these Y” are bounded. Infact, in this case, these converge uniformly to Y on [0,7]. Thus this is an example of thesituation in the above definition. In this case, the integrand would be bounded by C forsome C ande( [caten'r) = 2 (ory) =e (\jar (ry?) <=0by assumption. Hence, by the dominated convergence theorem,T: yn 2 Tp _time ( [ ly —Y"|]2, a [aM] ) 0.What if [M]°” were bounded and absolutely continuous with respect to Lebesgue mea-sure? This could be the case if you had Tt, a stopping time of the formTp = inf {t : [M](t) > p}Then if Y € L?([0,7] x Q,H), and progressively measurable there are left step functionswhich converge to Y in L? ({0,T] x Q,H). Say d[|M*”] =k(t,@)dm where k is bounded.ThenT TE (/ y-¥"l d(M|" ) =E (/ Iv —¥" tar) +00 0