70.4. THE NAVIER−STOKES EQUATIONS 2409

for all w ∈V . This is to say that

R−1u′n (t)+PnR−1A(un (t))+PnR−1N̂ (un (t)) = PnR−1f(t) .

Now the projection map decreases norms and R−1 preserves norms. Hence∥∥u′n (t)∥∥

V ′ =∥∥R−1u′n (t)

∥∥V ≤ ∥A(un (t))∥V ′ +

∥∥N̂ (un (t))∥∥

V ′ +∥f(t)∥V ′ ,

from which it follows that u′n is bounded in L2 ([0,T ] ;V ′). Indeed, this is the case becauseA(un) and N̂ (un) are both bounded in L2 ([0,T ] ;V ′) . The term

∥∥N̂ (un (t))∥∥

V ′ can be splitfurther into terms involving ∥N (un)∥ ,∥B(un,q)∥ , and ∥B(q,un)∥. For example, considerN (un) which is the least obvious. Let w ∈ L2 ([0,T ] ;V ) . From the definitions,∣∣∣⟨N (un) ,w⟩L2([0,T ],V )

∣∣∣= ∣∣∣∣∫ T

0

∫U

uniun jw j,idxdt∣∣∣∣

≤ C∫ T

0∥w(t)∥V |un|2H dt

≤ C∥w∥L2([0,T ],V )C (u0, f,q,T,ω) .

We have now shown that

supt∈[0,T ]

|un (t,ω)|2H +∫ T

0∥un(s,ω)∥2

W ds+∥∥u′n(ω)

∥∥L2([0,T ];V ′) ≤C (u0, f,q,T,ω) . (70.4.8)

This condition holds for all ω. Now for each ω, one can take a subsequence such that asolution to the evolution equation is obtained. Then, when this is done, we will apply themeasurable selection result to obtain a product measurable solution.

It follows from the above estimate 70.4.8 that there is a subsequence, still denoted as nand a function u(t,ω) such that

un→ u weak ∗ in L∞ ([0,T ] ;H) , (70.4.9)

u′n→ u′ weakly in L2 ([0,T ] ;V ′) ,un→ u weakly in L2 ([0,T ] ;W ) ,

un→ u strongly in L2 ([0,T ] ;H) . (70.4.10)

This last convergence follows from Theorem 70.4.1. The sequence is bounded in the spaceL2 ([0,T ] ;W ) and the derivative is bounded in L2 ([0,T ] ;V ′) so such a strongly convergentsubsequence exists. Since A is linear, we can also assume that

Aun→ Au weakly in L2 ([0,T ] ;W ′) . (70.4.11)

70.4. THE NAVIER—STOKES EQUATIONS 2409for all w € V. This is to say thatRoluy, (t) + PyR7'A (Un (t)) + PaR7'N (uy (t)) = PrRE(t).Now the projection map decreases norms and R~! preserves norms. HenceJa fy = [Rl Oly SMA Can (Dye + A (an) Iyer + Olefrom which it follows that u’, is bounded in L? ((0,7];V’). Indeed, this is the case becauseA(un) and N (u,) are both bounded in L? ((0,7];V’). The term ||N (un (¢)) lly can be splitfurther into terms involving ||N (u,)||, ||B (un, q)||, and ||B(q,u,,)|]. For example, considerN (uy) which is the least obvious. Let w € L? ([0,7];V). From the definitions,‘TopI (Un) W)72((0,7),v) | = | [ I UniUln jW j,idxdtIAT2Cf wll lualiatCc \| Wl]22((0,7),v) C (uo, f, q, T, @) .lAWe have now shown thatTsup, [i (off, + f llun(s,@) ly ds + [lu (®) |p Go.7.77 <C(uo,f,q,7,@). (70.4.8)te(0,This condition holds for all @. Now for each @, one can take a subsequence such that asolution to the evolution equation is obtained. Then, when this is done, we will apply themeasurable selection result to obtain a product measurable solution.It follows from the above estimate 70.4.8 that there is a subsequence, still denoted as nand a function u(t, @) such thatu, > u weak * in L” ([0,7];H), (70.4.9)u,, > u’ weakly in L? ([0,7];V’),u,, — u weakly in L? ([0,7];W),u, — u strongly in L? ((0,7];H). (70.4.10)This last convergence follows from Theorem 70.4.1. The sequence is bounded in the spaceL’ ({0,T];W) and the derivative is bounded in L? ({0,7];V’) so such a strongly convergentsubsequence exists. Since A is linear, we can also assume thatAu, —> Au weakly in L? ({0,7];W’) . (70.4.11)