19.9. COMPACT OPERATORS IN BANACH SPACE 557

19.9 Compact Operators in Banach SpaceIn general for A ∈L (X ,Y ) the following definition holds.

Definition 19.9.1 Let A ∈L (X ,Y ) . Then A is compact if whenever B ⊆ X is a boundedset, AB is precompact. Equivalently, if {xn} is a bounded sequence in X , then {Axn} has asubsequence which converges in Y.

An important result is the following theorem about the adjoint of a compact operator.

Theorem 19.9.2 Let A∈L (X ,Y ) be compact. Then the adjoint operator, A∗ ∈L (Y ′,X ′)is also compact.

Proof: Let {y∗n} be a bounded sequence in Y ′. Let B be the closure of the unit ballin X . Then AB is precompact. Then it is clear that the functions {y∗n} are equicontinuousand uniformly bounded on the compact set, A(B). By the Ascoli Arzela theorem, there is asubsequence

{y∗nk

}which converges uniformly to a continuous function, f on A(B). Now

define g on AX by

g(Ax) = ||x|| f(

A(

x||x||

)),g(A0) = 0.

Thus for x1,x2 ̸= 0, and a,b scalars,

g(aAx1 +bAx2) ≡ ||ax1 +bx2|| f(

A(ax1 +bx2)

||ax1 +bx2||

)≡ lim

k→∞

||ax1 +bx2||y∗nk

(A(ax1 +bx2)

||ax1 +bx2||

)= lim

k→∞ay∗nk

(Ax1)+by∗nk(Ax2)

= a limk→∞

||x1||y∗nk

(Ax1

||x1||

)+b lim

k→∞

||x2||y∗nk

(Ax2

||x2||

)= a ||x1|| f

(Ax1

||x1||

)+b ||x2|| f

(Ax2

||x2||

)≡ ag(Ax1)+bg(Ax2)

showing that g is linear on AX . Also

|g(Ax)|= limk→∞

∣∣∣∣||x||y∗nk

(A(

x||x||

))∣∣∣∣≤C ||x||∣∣∣∣∣∣∣∣A( x

||x||

)∣∣∣∣∣∣∣∣=C ||Ax||

and so by the Hahn Banach theorem, there exists y∗ extending g to all of Y having the sameoperator norm.

y∗ (Ax) = limk→∞

||x||y∗nk

(A(

x||x||

))= lim

k→∞y∗nk

(Ax)

19.9. COMPACT OPERATORS IN BANACH SPACE 55719.9 Compact Operators in Banach SpaceIn general for A € (X,Y) the following definition holds.Definition 19.9.1 Let A € & (X,Y). Then A is compact if whenever B C X is a boundedset, AB is precompact. Equivalently, if {x,} is a bounded sequence in X, then {Ax;,} has asubsequence which converges in Y.An important result is the following theorem about the adjoint of a compact operator.Theorem 19.9.2 Let A € ¥ (X,Y) be compact. Then the adjoint operator, A* € & (Y',X’)is also compact.Proof: Let {y;} be a bounded sequence in Y’. Let B be the closure of the unit ballin X. Then AB is precompact. Then it is clear that the functions {y;} are equicontinuousand uniformly bounded on the compact set, A (B). By the Ascoli Arzela theorem, there is asubsequence {yn } which converges uniformly to a continuous function, f on A (B). Nowdefine g on AX byeax) =i (4 (=) ) .9(a0) =o.Thus for x;,x2 40, and a,b scalars,ax, +bx2g(aAx;+bAx) = Jani + bral (FE) |A (ax; + bx)= | b m \ Tax bani)jim Jani + nally, (G@E— lim any, (Ax1) + byn, (Ax2)k-00. Ax2_ aim ly (Sh ) bin ljallya, (= =)= altull (Tp) +blbelle (Te)ag (Ax) + bg (Ax2)showing that g is linear on AX. Alsolg (Ax)| = limXxX Xxsii, (45) )| sett ja) || =efim |Ibslyne (A (Gig laland so by the Hahn Banach theorem, there exists y* extending g to all of Y having the sameoperator norm.* (Ax) = li * (a(—_)) =limy* (Ay" (Ax) = lim |l11¥n, inl = jim y;, (Ax)