832 CHAPTER 25. NONLINEAR OPERATORS
The right side is bounded and so it follows that the left side is also bounded. Therefore,∥un∥ must be bounded. Taking a subsequence and using the assumption that V is reflexive,we can obtain
un→ u weakly in V
By the fact that convex closed sets are weakly closed also, it follows that u∈K. Also, givenM, eventually all ∥un∥ and ∥u∥ are less than M. Now from the inequality,
⟨Aun,un− v⟩ ≤ ⟨ f ,un− v⟩
Thus⟨Aun,un−u⟩+ ⟨Aun,u− v⟩ ≤ ⟨ f ,un−u⟩+ ⟨ f ,u− v⟩
Then taking limsupn→∞ one gets
lim supn→∞
⟨Aun,un−u⟩+ ⟨ξ ,u− v⟩ ≤ ⟨ f ,u− v⟩
This holds for v ∈ Km where m is arbitrary. Hence one could let vm→ u. Thus eventually∥vm∥< M and so for large m,vm ∈ Km. Then it follows that
lim supn→∞
⟨Aun,un−u⟩ ≤ 0.
Consequently, by the assumption that A is pseudomonotone on K, for every v ∈ K,
⟨Au,u− v⟩ ≤ lim infn→∞⟨Aun,un− v⟩ (*)
for all v ∈ K. Then from the inequality obtained from Browder’s lemma,
⟨Aun,un− v⟩V ′,V ≤ ⟨ f ,un− v⟩V ′,V
and so * implies on taking liminf that for all v ∈ K,
⟨Au,u− v⟩V ′,V ≤ ⟨ f ,u− v⟩V ′,V
25.2 Duality MapsThe duality map is an attempt to duplicate some of the features of the Riesz map in Hilbertspace which is discussed in the chapter on Hilbert space.
Definition 25.2.1 A Banach space is said to be strictly convex if whenever ||x||= ||y|| andx ̸= y, then ∣∣∣∣∣∣∣∣x+ y
2
∣∣∣∣∣∣∣∣< ||x||.F : X→ X ′ is said to be a duality map if it satisfies the following: a.) ||F(x)||= ||x||p−1. b.)F(x)(x) = ||x||p, where p > 1.