766 CHAPTER 28. THE NORMAL DISTRIBUTION

and so E(X4)= 3σ4. By now you can see the pattern. If you continue this way, you find

the odd moments are all 0 and

E(X2m)=Cm

2)m. (28.7)

This is an important observation. In the case of X a random vector, you have φX (t) ≡E (exp(it ·X)) and by taking d

dt j, you can follow the above procedure to obtain E (X j) and

then by using successive differentiations, you can find E (Xni ) or any polynomial in the Xi

assuming the expectations exist.

28.4 Prokhorov and Levy TheoremsRecall one can define the characteristic function of a probability measure µ as

∫Rp eit·xdµ .

In a sense it is more natural. One can also generalize to replace Rp with E a Banach spacein which the dot product t ·x is replaced with t (x) where t ∈ E ′. However, the main interesthere is in Rp.

Definition 28.4.1 A set of Borel probability measures {µn}∞

n=1 defined on a Polishspace E is called “tight” if for all ε > 0 there exists a compact set, Kε such that

µn ([x /∈ Kε ])< ε

for all µn.

How do you determine in general that a set of probability measures is tight?

Lemma 28.4.2 Let E be a separable complete metric space and let Λ be a set of Borelprobability measures. Then Λ is tight if and only if for every ε > 0 and r > 0 there exists afinite collection of balls, {B(ai,r)}m

i=1 such that

µ

(∪m

i=1B(ai,r))> 1− ε

for every µ ∈ Λ.

Proof: If Λ is tight, then there exists a compact set, Kε such that

µ (Kε)> 1− ε

for all µ ∈ Λ. Then consider the open cover, {B(x,r) : x ∈ Kε} . Finitely many of thesecover Kε and this yields the above condition.

Now suppose the above condition and let

Cn ≡ ∪mni=1B(an

i ,1/n)

satisfy µ (Cn) > 1− ε/2n for all µ ∈ Λ. Then let Kε ≡ ∩∞n=1Cn. This set Kε is a compact

set because it is a closed subset of a complete metric space and is therefore complete, andit is also totally bounded by construction. For µ ∈ Λ,

µ(KC

ε

)= µ

(∪nCC

n)≤∑

nµ(CC

n)< ∑

n

ε

2n = ε

Therefore, Λ is tight. ■In case the Polish space is Rp, the case of most interest, there is a very nice condition

interms of characteristic functions which gives “tightness”.

766 CHAPTER 28. THE NORMAL DISTRIBUTIONand so E (X*) = 30+. By now you can see the pattern. If you continue this way, you findthe odd moments are all 0 andmE (X”") =, (07)". (28.7)This is an important observation. In the case of X a random vector, you have @ x (t) =E (exp (it: X )) and by taking 4. you can follow the above procedure to obtain E (X;) andJthen by using successive differentiations, you can find E (X;’) or any polynomial in the X;assuming the expectations exist.28.4 Prokhorov and Levy TheoremsRecall one can define the characteristic function of a probability measure pL as fpp edu.In a sense it is more natural. One can also generalize to replace R? with E a Banach spacein which the dot product €- x is replaced with t (x) where t € E’. However, the main interesthere is in R?.Definition 28.4.1 4 set of Borel probability measures {Ly}, defined on a Polishspace E is called “tight” if for all € > 0 there exists a compact set, Kg such thatM, ([w ¢ Ke]) <€for all ,.How do you determine in general that a set of probability measures is tight?Lemma 28.4.2 Let E be a separable complete metric space and let A be a set of Borelprobability measures. Then A is tight if and only if for every € > 0 and r > 0 there exists afinite collection of balls, {B(aj;,r)}""_, such thatLt (Um B(a.r)) >1l-eéfor every WEA.Proof: If A is tight, then there exists a compact set, Ke such thatU(Ke) > 1—-€for all yp € A. Then consider the open cover, {B(x,r) : x € Ke}. Finitely many of thesecover Kg and this yields the above condition.Now suppose the above condition and letCy = Um", B(a?,1/n)satisfy U(C,) > 1—e/2" for all wu € A. Then let Ke = M_,Cy. This set Ke is a compactset because it is a closed subset of a complete metric space and is therefore complete, andit is also totally bounded by construction. For wu € A,(KE) =u (rCS) $Ea (CH) < Dae =Therefore, A is tight. HiIn case the Polish space is R?, the case of most interest, there is a very nice conditioninterms of characteristic functions which gives “tightness”.