30.2. KOLMOGOROV ČENTSOV CONTINUITY THEOREM 815

Thus, there exists a sequence of mesh points {sn} converging to t such that

P(∥X (sn)−X (t)∥α > 2−n)≤ 2−n

Then by the Borel Cantelli lemma, there is a set of measure zero N such that for ω /∈N,∥X (sn)−X (t)∥α ≤ 2−n for all n large enough. Then

∥Y (t)−X (t)∥ ≤ ∥Y (t)−Y (sn)∥+∥X (sn)−X (t)∥

which shows that, by continuity of Y, for ω not in an exceptional set of measure zero,∥Y (t)−X (t)∥= 0.

It remains to verify the assertion about Holder continuity of Y . Let 0≤ s < t ≤ T. Thenfor some n,

2−(n+1)T ≤ t− s≤ 2−nT (30.16)

Thus∥Y (t)−Y (s)∥ ≤ ∥Y (t)−Xn (t)∥+∥Xn (t)−Xn (s)∥+∥Xn (s)−Y (s)∥

≤ 2 supτ∈[0,T ]

∥Y (τ)−Xn (τ)∥+∥Xn (t)−Xn (s)∥ (30.17)

Now∥Xn (t)−Xn (s)∥

t− s≤ ∥Xn (t)−Xn (s)∥

2−(n+1)T

From 30.16 a picture like the following must hold in which tn+1k−1 ≤ s < tn+1

k < t ≤ tn+1k+1 .

s t tn+1k+1tn+1

ktn+1k−1

Therefore, from the above, 30.16,

∥Xn (t)−Xn (s)∥t− s

≤∥∥X(tn+1k−1

)−X

(tn+1k

)∥∥+∥∥X(tn+1k+1

)−X

(tn+1k

)∥∥2−(n+1)T

≤ C2nMn+1

It follows from 30.17,

∥Y (t)−Y (s)∥ ≤ 2∥Y −Xn∥∞+C2nMn+1 (t− s)

Next, letting γ < β/α, and using 30.16,

∥Y (t)−Y (s)∥(t− s)γ ≤ 2

(T−12n+1)γ ∥Y −Xn∥∞

+C2n (2−n)1−γ Mn+1

= C2nγ (∥Y −Xn∥∞+Mn+1)

The above holds for any s, t satisfying 30.16. Then

sup{∥Y (t)−Y (s)∥

(t− s)γ ,0≤ s < t ≤ T, |t− s| ∈[2−(n+1)T,2−nT

]}

30.2. KOLMOGOROV CENTSOV CONTINUITY THEOREM 815Thus, there exists a sequence of mesh points {s, } converging to t such thatP(\|X (sn) —X (t)||* >2-") <2"Then by the Borel Cantelli lemma, there is a set of measure zero N such that for @ ¢N,||X (sn) —X (t)||° < 27” for all n large enough. ThenIP) —X OI SP ©) —¥ Gn) | + 1X (Sn) —X (|which shows that, by continuity of Y, for @ not in an exceptional set of measure zero,I (1) —X (|| =0.It remains to verify the assertion about Holder continuity of Y. LetO<s<t<T7. Thenfor some n,207 <t—s<2°T (30.16)ThusY(t) —¥ (s)|] < |]¥ ©) —Xn (0) + [Xn (0) — Xn (5) |] + |] Xn (5) — ¥ (s)||<2 sup IY (2) —Xn (2) +X () Xa) (30.17)tE(0,T]Now|Xn (t) — Xn (s)|| < [Xn (t) —Xn(s)|t—s ~ Q-@+)) 7From 30.16 a picture like the following must hold in which wel <s< gel <t< Haae aTherefore, from the above, 30.16,Wn =Xn(s\ih 2 PE) =X (I+ |x (ED) =X (|t—s ~ 2-(+1)TC2"My 1IAIt follows from 30.17,II¥ (t) —¥ ()|| $2 |]¥ —Xnl]e. + C2"Mn41 (t— 8)Next, letting y < B/a, and using 30.16,IY (1) = ¥ (s)I|(1—s)"IA2(T12"1)" Wy — x, C2" (2-7) Ma= €2"7(||¥ ~Xnl..+Mn+1)The above holds for any s,t satisfying 30.16. ThenY(t)-Ysup {lo <s<t<T,|t—s|€ Ppenr.s-e7| |