38.3. AN INTRINSIC NORM 1309

Now for α > 0,

G(αz) =∫|t|−n−2s ∣∣(eit·αz−1

)∣∣2 dt

=∫|t|−n−2s ∣∣(eiαt·z−1

)∣∣2 dt

=∫ ∣∣∣ r

α

∣∣∣−n−2s ∣∣(eir·z−1)∣∣2 1

αn dr

= α2s∫|r|−n−2s ∣∣(eir·z−1

)∣∣2 dr = α2sG(z) .

Also G is continuous and strictly positive. Letting

0 < m(s) = min{G(w) : |w|= 1}

andM (s) = max{G(w) : |w|= 1} ,

it follows from this, and letting α = |z| ,w≡ z/ |z| , that

G(z) ∈(

m(s) |z|2s ,M (s) |z|2s).

More can be said but this will suffice. Also observe that for s ∈ (0,1) and b > 0,

(1+b)s ≤ 1+bs, 21−s (1+b)s ≥ 1+bs.

In what follows, C (s) will denote a constant which depends on the indicated quantitieswhich may be different on different lines of the argument. Then from 38.3.11,∫ ∫

|Dα u(x)−Dα u(y)|2 |x−y|−n−2s dxdy

≤ M (s)∫|FDα u(z)|2 |z|2s dz

= M (s)∫|Fu(z)|2 |zα |2 |z|2s dz.

No reference was made to |α|=m and so this establishes the top half of 38.3.10. Therefore,

|||u|||2m+s ≡ ||u||2m,2,Rn + ∑|α|=m

∫ ∫|Dα u(x)−Dα u(y)|2 |x−y|−n−2s dxdy

≤ C∫ (

1+ |z|2)m|Fu(z)|2 dz+M (s)

∫|Fu(z)|2 ∑

|α|=m|zα |2 |z|2s dz

Recall that

∑|α|≤m

z2α11 · · ·z2αn

n ≤

(1+

n

∑j=1

z2j

)m

≤C (n,m) ∑|α|≤m

z2α11 · · ·z2αn

n . (38.3.12)

38.3. AN INTRINSIC NORM 1309Now for a > 0,G(az) = / It)” | (et — 1) Par= fr Oe,= 1h )P on= « Sateen rl.Also G is continuous and strictly positive. Letting—n—2sett _0 < m(s) = min{G(w) : |w| = 1}andM (s) = max{G(w) : |w| = 1},it follows from this, and letting a@ = |z|,w = z/ |z| , thatG(2) € (m(s) al? ,M (5) |2I*).More can be said but this will suffice. Also observe that for s € (0,1) and b > 0,(1+b)' <14b°, 2!-8(14b) >145°.In what follows, C(s) will denote a constant which depends on the indicated quantitieswhich may be different on different lines of the argument. Then from 38.3.11,J [\reucs) — Duty) [x yl" axdyIAM(s) [ \FD%u(2)[?|al* ds_— a|2 |, 12s= M(s) [ \Pu(a)P "(al az.No reference was made to |@| = m and so this establishes the top half of 38.3.10. Therefore,2 _ 2 —n—2.lallfies = llellmame+ DL ff %u (x) —D%u(y)/? x—yl” *adxdy|a|=m< cf (1+kP)" sonar V2" |? al? de|a|=mRecall thatmn) eee (£3) <C(nym) Yo git gpn, (38.3.12)j=l\a|<m |a|<m