440 CHAPTER 16. HAUSDORFF MEASURE

xU

WVy

This is a picture of two balls of radius r = |x−y| in Rp, U and V having centers at xand y respectively, which intersect in the set W. The center of U is on the boundary of Vand the center of V is on the boundary of U as shown in the picture. There exists a constantC, independent of r depending only on p such that mp(W )

mp(U) =mp(W )mp(V ) =

1C . You could compute

this constant if you desired but it is not important here.Then

|u(x)−u(y)| =1

mp (W )

∫W|u(x)−u(y)|dz

≤ 1mp (W )

∫W|u(x)−u(z)|dz+

1mp (W )

∫W|u(z)−u(y)|dz

=C

mp (U)

[∫W|u(x)−u(z)|dz+

∫W|u(z)−u(y)|dz

]≤ C

mp (U)

[∫U|u(x)−u(z)|dz+

∫V|u(y)−u(z)|dz

](16.4)

Now consider these two terms. Let q > p. Consider the first term.Letting U0 denote the ball of the same radius as U but with center at 0.

1mp (U)

∫U|u(x)−u(z)|dz =

1mp (U0)

∫U0

|u(x)−u(z+x)|dz

=1

mp (U0)

∫U0

∣∣∣∣∫ 1

0∇u(x+ tz) ·zdt

∣∣∣∣dz≤ 1mp (U0)

∫ 1

0

∫U0

|∇u(x+ tz)| |z|dzdt

≤ 1mp (U0)

∫ 1

0

(∫U0

|∇u(x+ tz)|q dz)1/q(∫

U0

|z|q/(q−1) dz)(q−1)/q

=1

mp (U0)

∫ 1

0

(∫U0

|∇u(x+ tz)|q dz)1/q(∫

Sp−1

∫ r

q/(q−1)ρ

p−1dρdσ

)(q−1)/q

= Cpqr

1q (q−p+pq)

mp (U0)

∫ 1

0

(∫U0

|∇u(x+ tz)|q dz)1/q

dt

=Cpq

α (p)r1− p

q

mp (U0)

∫ 1

0

(∫U0

|∇u(x+ tz)|q dz)1/q

dt

where Cpq = σ p−1(Sp−1

)(q−1)/q(

q−1q−p+pq

)(q−1)/q.

Now estimate the last term.∫ 1

0

(∫U0

|∇u(x+ tz)|q dz)1/q

dt =∫ 1

0

(1t p

∫tU0

|∇u(x+v)|q dv)1/q

dt

≤∫ 1

0

1t p/q

(∫U0

|∇u(x+v)|q dv)1/q

dt

440 CHAPTER 16. HAUSDORFF MEASUREThis is a picture of two balls of radius r = |a — y| in R?, U and V having centers at xand y respectively, which intersect in the set W. The center of U is on the boundary of Vand the center of V is on the boundary of U as shown in the picture. There exists a constantC, independent of r depending only on p such that 7 a = 7 - = é. You could computethis constant if you desired but it is not important here.Thentea) ay) = sy | ml) mania<a y ltl) —WNldet 5p | lule) wala_ me) I, lu (a) —u( 2)\dz+ | lu(z) —u( w)\de|< yf me-mealace [| mo)—m(a)iae] 64)Now consider these two terms. Let g > p. Consider the first term.Letting Up denote the ball of the same radius as U but with center at 0.! 1rig Ty yl) MAE Fay | yy mle) mle tale‘I/ Vu(ax+tz)-zdt01 1 ]= —__ d<—— | / Vu(a+tz)||z|dzdtmay vy mp (U up| ( Mle1 “| . ; 1/q 7 pp aq) (q—-1)/q_— Vu(a+tz)|\‘d / _ az)mn ( Up u(w +12) :) (fi Z1 1 1/q . oamata (f. Vu(v-+r2))"d) (ff pil" papaMp4 (a-p+pa) , 1/q= C, aa A (/, Vu(a+tz as) dtPq Mp (Uo) | )|1Cog 9 -G fl ; \/q= Vu(a+tz as) dta (9) mp a) ( yy Ve Hie)_ 1 \@-)/where Cyg = pi (sP-1)4 1)/q E=) aqNow estimate the last term.1 1/q 1/4 1/q[GU IYu(e +12)|"d:) dt = [Gl Vu(e+v)/?av) di0 Uo 0 \tP StUIAoo~}-RayaNSF<J=—8+e~~"TSaX<NY=OSa_~