2240 CHAPTER 65. STOCHASTIC INTEGRATION

Then for x ∈ Q1/2U,

L

∑j=1

√λ je j⊗Q1/2U

J∗e j√λ j

(x) =L

∑j=1

√λ je j

(J∗e j√

λ j,x

)Q1/2(U)

=L

∑j=1

√λ je j

(e j√λ j

,Jx

)U1

=L

∑j=1

e j (e j,Jx)U1

=∞

∑j=1

e j (e j,Jx)U1= Jx.

(J(

Q1/2 (U))⊆ span(e1, · · · ,eL) if L < ∞

)Thus,

J =L

∑j=1

√λ je j⊗Q1/2U

J∗e j√λ j

It follows that an orthonormal basis in JQ1/2U is{

JJ∗e j√λ j

}L

j=1. This is because an or-

thonormal basis for Q1/2U is{

J∗ek√λ k

}. Since J is one to one, it preserves norms between

Q1/2U and JQ1/2U . Let Φ ∈L2(JQ1/2U,H

). Then by the discussion of Hilbert Schmidt

operators given earlier, in particular the demonstration that these operators are compact,

Φ =∞

∑i=1

∑j=1

φ i j fi⊗JQ1/2UJJ∗e j√

λ j

where { fi} is an orthonormal basis for H. In fact,{

fi⊗JJ∗e j√

λ j

}i, j

is an orthonormal basis

for L2(JQ1/2U,H

)and ∑i ∑ j φ

2i j < ∞, the φ i j being the Fourier coefficients of Φ. Then

consider

Φn =n

∑i=1

n

∑j=1

φ i j fi⊗JQ1/2UJJ∗e j√

λ j(65.4.6)

Consider one of the finitely many operators in this sum. For x ∈ JQ1/2U, since J preservesnorms,

fi⊗JQ1/2UJJ∗e j√

λ j(x)≡ fi

(JJ∗e j√

λ j,x

)JQ1/2U

= fi

(J∗e j√

λ j,J−1x

)Q1/2U

= fi

(e j√λ j

,JJ−1x

)U1

= fi

(e j√λ j

,x

)U1

≡ Λi j (x)

Recall how, since J is one to one, it preserves norms and inner products. Now Λi j makessense from the above formula for all x ∈U1 and is also a continuous linear map from U1 to

2240 CHAPTER 65. STOCHASTIC INTEGRATIONThen for x € Q!/2U,YE VFeicar 0) =¥ Vie ( Gi]J€j Sal/u x) = jej 1Xj=l e Aj j=l Aj g'/2(u)Thus,L *J*e;J= y 4/A jej® 12y —Lj=l ° VAiJS*e;vii\ Since J is one to one, it preserves norms betweenLIt follows that an orthonormal basis in JQ!/2U is { \ . This is because an or-j=lthonormal basis for Q!/2U is ¢ 2%ko'/2u and Jo'/2u. Let BEY (Jo!/?U,H) . Then by the discussion of Hilbert Schmidtoperators given earlier, in particular the demonstration that these operators are compact,co 00JJ*e;©=) Y Gi fi ® ory —ES oes oei=1 j=lJS* ej . .—_ is an orthonormal basisVAj h,for LZ (JO'/?U,H) and Y;¥; 7; < ce, the @;; being the Fourier coefficients of ®. Thenconsiderwhere { f;} is an orthonormal basis for H. In fact, { fi® yy 6 Fi®porry eet (65.4.6)n= ijJi @Q\2u A.i=1 j=1 / e V AjConsider one of the finitely many operators in this sum. For x € J Q!/2U, since J preservesnorms,JS*e;JSF*e; Je;fi®yor/2 Lone al s) =a( Los)vou VAj Vaj Jo'/2u V Aj o'/uej ej= fi urs) ai s] =Aij(4 ly Vai) y i@)Recall how, since J is one to one, it preserves norms and inner products. Now A;; makessense from the above formula for all x € U; and is also a continuous linear map from U; to